Question

我有一个来自数据库的id的链接。当我点击它时，如何通过向他们申请相同的ID来将此ID复制到2个按钮？看哪我尝试：

$('.godown').click(function() {
var godown = $(this).attr('id');
// How can I copy the variable **godown ** to the buttons so that they have the save id as godown ?
});

JQUERY

from flask import Flask, request, send_file, Response, make_response
from flask_restful  import Resource, Api
import matplotlib.pyplot as plt
from io import StringIO, BytesIO
import numpy as np
import json
import random
from matplotlib.backends.backend_agg import FigureCanvasAgg as FigureCanvas
from matplotlib.figure import Figure
import pandas as pd


app = Flask(__name__)
api = Api(app)

app.debug = True

class Graph(Resource):
    def get(self):
        fig = Figure()
        axis = fig.add_subplot(1, 1, 1)

        xs = range(100)
        ys = [random.randint(1, 50) for x in xs]

        axis.plot(xs, ys)
        canvas = FigureCanvas(fig)
        output = BytesIO()
        canvas.print_png(output)
        response = make_response(output.getvalue())
        response.mimetype = 'image/png'
        return response

class PltGraph(Resource):
    def get(self):

        fig = Figure()
        xs = range(100)
        ys = [random.randint(1, 50) for x in xs]
        plt.plot(xs,ys)
        plt.ylabel("Y label")
        plt.xlabel("X label")
        plt.title("x and y")
        canvas = FigureCanvas(fig)
        output = BytesIO()
        canvas.print_png(output)
        response = make_response(output.getvalue())
        response.mimetype = 'image/png'
        print(response)
        return response


api.add_resource(Graph,'/Graph.png')
api.add_resource(PltGraph,'/PltGraph.png')

app.run(host='0.0.0.0', port= 81)

由于

将id元素复制到其他元素

0 个答案: