Question

我试图从字符串中删除特定数量的重复字母并显示字符串。例如，我有一个像＆＃34; sdfgsd sdfd jkhj dfg sdf＆＃34;我想从这个字符串中删除3次以上的重复字母并再次显示。我试图用python做到这一点我怎样才能做到这一点。这是我的代码：

chars = "abcdefghijklmnopqrstuvwxyz"
    check_string = "aanbg sdfsd futy asdf sdferg gyıuy"
    for char in chars:
        count = check_string.count(char)
//3 and more than 3 times repeated letters removing from string
        if count >= 3:
        remove (char, count)
        print("check_string")

Answer 1

这应该有效：

>>> from collections import Counter

>>> check_string = "aanbg sdfsd futy asdf sdferg gyıuy"
>>> letter_occurrances = Counter(check_string).items()
>>> letter_occurrances
dict_items([('a', 3), ('n', 1), ('b', 1), ('g', 3), (' ', 5), ('s', 4), ('d', 4), ('f', 4), ('u', 2), ('t', 1), ('y', 3), ('e', 1), ('r', 1), ('ı', 1)])    
>>> for key, value in letter_occurrances:
       if value>=3 and key!=' ':
          check_string = check_string.replace(key, '')
>>> check_string
'nb  ut  er ıu'

如果您想自己实施letter_occurrances：

>>> from collections import defaultdict

>>> check_string = "aanbg sdfsd futy asdf sdferg gyıuy"
>>> letter_occurrances = defaultdict(int)
>>> for letter in check_string:
       letter_occurrances[letter] += 1
>>> letter_occurrances
defaultdict(<class 'int'>, {'a': 3, 'n': 1, 'b': 1, 'g': 3, ' ': 5, 's': 4, 'd': 4, 'f': 4, 'u': 2, 't': 1, 'y': 3, 'e': 1, 'r': 1, 'ı': 1})
>>> for key, value in letter_occurrances:
       if value>=3 and key!=' ':
          check_string = check_string.replace(key, '')
>>> check_string
'nb  ut  er ıu'

从Python中删除字符串中特定数量的重复字母

1 个答案: