Question

以下代码导致Eclipse显示死代码警告，尽管代码可以访问。我在这里遗漏了什么，或者这是一个Eclipse / javac错误？

//bind to $name
if ($stmt = $conn->prepare("SELECT Industry FROM industries")) {
    $stmt->bind_result($name);
    $OK = $stmt->execute();
}
//put all of the resulting names into a PHP array
$result_array = Array();
while($stmt->fetch()) {
    $result_array[] = $name;
}
//convert the PHP array into JSON format, so it works with javascript
$json_array = json_encode($result_array);

代码打印import java.util.ArrayList; public class DeadCodeDemo { public static class SomeClosable implements AutoCloseable { @Override public void close() throws Exception { } } public static ArrayList<String> throwRuntime() { throw new RuntimeException(); } public static void main(String[] args) { ArrayList<String> list = null; try { try (SomeClosable c = new SomeClosable()) { list = throwRuntime(); } try (SomeClosable c = new SomeClosable()) { list.clear(); } } catch (Exception e) { if (list != null) { // Warning: Redundant null check: The variable list cannot be null at this location System.out.println("List is not null"); } else { System.out.println("List is null"); // Warning: Dead code } } } }

我使用Eclipse 4.7.3a（Oxygen.3a）和JDK 8_162

Answer 1

我认为它是this issue，仍处于打开状态。

请记住，这是Eclipse warning，而不是javac - 在问题得到解决之前，这几乎是你应该关心的事情（即使现在已经7岁了）

Eclipse为可访问的代码提供了死代码警告

1 个答案: