// All methods could be called like this but it will result in a lof of code that is nearly duplicated
//internal void AddOrUpdateClassifications()
//{
// var result = _IntegrationApiService.GetClassifications();
//
// //foreach (var value in result)
// //{
// // try
// // {
// // var current = _DbContext.Classifications.Find(value.ClassificationId);
// // if (current == null)
// // {
// // _DbContext.Classifications.Add(value);
// // }
// // else
// // {
// // _DbContext.Entry(current).CurrentValues.SetValues(value);
// // }
// // }
// // catch (Exception e)
// // {
// // throw;
// // }
// //}
// //_DbContext.SaveChanges();
//}
internal void AddOrUpdateClassifications()
{
var result = _IntegrationApiService.GetClassifications();
GenericAddOrUpdate(result, "ClassificationId");
}
internal void AddOrUpdateFeeCalculations(string businessSystemId, int caseId)
{
var result = _IntegrationApiService.GetFeeCalculation(businessSystemId, caseId);
//This does not work
//GenericAddOrUpdate(result, "BusinessSystemId", "CaseId", "Action", "Cycle", "RateNo");
}
private void GenericAddOrUpdate<T>(ICollection<T> values, params string[] keyValues) where T : class
{
foreach (var value in values)
{
try
{
var keyList = new List<object>();
foreach (var keyValue in keyValues)
{
var propertyInfo = value.GetType().GetProperty(keyValue);
var propertyValue = propertyInfo.GetValue(value);
keyList.Add(propertyValue);
}
var someDbSet = _DbContext.Set(typeof(T));
//I need to add all the values from keyList here. I can't add the list directly since I will get the error below. Example with keyList[0] to show working code
//The specified parameter type 'System.Collections.Generic.List`1[[System.Object, mscorlib, Version=4.0.0.0, Culture=neutral, //PublicKeyToken=b77a5c561934e089]]' is not valid. Only scalar types, such as System.Int32, System.Decimal, System.DateTime, and System.Guid, are supported.
var current = someDbSet.Find(keyList[0]);
if (current == null)
{
someDbSet.Add(value);
}
else
{
_DbContext.Entry(current).CurrentValues.SetValues(value);
}
}
catch (Exception e)
{
throw;
}
}
_DbContext.SaveChanges();
}
需要“{5662}”替换为“[5662](htttps://somelink.com/task/5662)”使用bash
任务编号的计数可能等于或大于4位数
任何想法?
答案 0 :(得分:2)
使用bash正则表达式和扩展功能
text="TASK {5662}: Task definition"
re='^TASK \{([0-9]{4,})\}: Task definition$'
if [[ $text =~ $re ]]; then
id=${BASH_REMATCH[1]}
result=${text/"{$id}"/"[$id](htttps://somelink.com/task/$id)"}
else
result=
fi
答案 1 :(得分:1)
解决方案1: 关注awk
可能对您有所帮助。 (我不是硬编码数字只是通过正则表达式匹配它然后放置新值)
awk --re-interval -v val="[5662](htttps://somelink.com/task/5662)" 'match($0,/[0-9]{4}/){print substr($0,1,RSTART-1) val substr($0,RSTART+RLENGTH+1)}' Input_file
同样--re-interval
适用于awk
的旧版本,适用于awk
的新版本,也可能不需要。{/ p>
解决方案第二: 使用sed
硬编码数字:
sed 's#{5662}#[5662](htttps://somelink.com/task/5662)#' Input_file