Question

我试图在模型的基础上制作表格。麻烦的是，当我通过category创建django shell时，请说＆＃34; Wedding＆＃34;类别，id=1和name = "weddings"，当我在下拉列表中显示（以html格式）时，它显示为Categories object (1)，我希望它显示为名称，即{ {1}}。

与documentation中一样，我知道我可以在weddings表单类中附加labels，但我不完全理解如何动态显示所有类别名称而不是类别对象1,2,3,4。

Models.py

Meta

Forms.py

class categories(model.Model):
    id = models.AutoField(primary_key =True)
    name = models.Charfield(max_length = 50)

class Event(models.Model):
    id = models.AutoField(primary_key =True)
    category = models.ForeignKey(Categories,on_delete=models.SET_NULL,null = True)
    owner = models.Charfield(max_length = 50)

因此渲染表单时的实际结果是：

class EventForm(forms.ModelForm):
class Meta:
    model = Event
    fields = ['category','person','owner']

期望的结果：

Category:(dropdown) - Categories object (1)

Answer 1

class categories(model.Model):
    id = models.AutoField(primary_key =True)
    name = models.Charfield(max_length = 50)

    def __str__(self):
        return self.name

class Event(models.Model):
    id = models.AutoField(primary_key =True)
    category = models.ForeignKey(Categories,on_delete=models.SET_NULL,null = True)
    owner = models.Charfield(max_length = 50)


    def __str__(self):
        return self.owner

只需将这些小魔术函数添加到模型类中即可。

Django表单字段显示名称

1 个答案: