Question

基于以下link：我们可以将表转换为xml

表格

USE AdventureWorks2012;  
  GO  
  SELECT ProductModelID, Name  
  FROM Production.ProductModel  
  WHERE ProductModelID=122 or ProductModelID=119  
  FOR XML RAW, XMLSCHEMA  
  GO

XML：

<xsd:schema targetNamespace="urn:schemas-microsoft-com:sql:SqlRowSet1"         
xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
xmlns:sqltypes="http://schemas.microsoft.com/sqlserver/2004/sqltypes" 
elementFormDefault="qualified">  
<xsd:import namespace="http://schemas.microsoft.com/sqlserver /2004/sqltypes" schemaLocation="http://schemas.microsoft.com/sqlserver/2004/sqltypes/sqltypes.xsd" />  
 <xsd:element name="row">  
<xsd:complexType>  
  <xsd:attribute name="ProductModelID" type="sqltypes:int" use="required" />  
  <xsd:attribute name="Name" use="required">  
    <xsd:simpleType sqltypes:sqlTypeAlias="[AdventureWorks].[dbo].[Name]">  
      <xsd:restriction base="sqltypes:nvarchar" sqltypes:localeId="1033" sqltypes:sqlCompareOptions="IgnoreCase IgnoreKanaType IgnoreWidth" sqltypes:sqlSortId="52">  
        <xsd:maxLength value="50" />  
      </xsd:restriction>  
    </xsd:simpleType>  
  </xsd:attribute>  
  </xsd:complexType>  
 </xsd:element>  
</xsd:schema>  
   <row xmlns="urn:schemas-microsoft-com:sql:SqlRowSet1" ProductModelID="122" Name="All-Purpose Bike Stand" />  

<row xmlns="urn:schemas-microsoft-com:sql:SqlRowSet1" ProductModelID="119" Name="Bike Wash" />

基于以前的xml，我们如何创建sql表以便将数据插回到表：Production.ProductModel？我需要一种适用于所有表而不是特定表的通用方法。

例如，我需要类似以下内容但更聪明（例如，从xmlschema中检索有关列名称及其类型的数据。）

DECLARE   @xml XML
    , @table NVARCHAR(50)

DECLARE   @COLUMNS NVARCHAR(MAX)
    , @COLUMNSBYTYPE NVARCHAR(MAX)

SET @xml = '<row><ProductModelID>1</ProductModelID><Name>Test</Name></row>
        <row><ProductModelID>2</ProductModelID><Name>Test2</Name></row>'

SET @table = 'Production.ProductModel'

-- get columns name and their types
SET @COLUMNSBYTYPE = stuff(
                        (
                            select ',T.X.value(''('+C.Name+'/text())[1]'', ''' + 'nvarchar(max)' + ''') as '+C.Name
                            from @xml.nodes('row[1]/*') as T(X)
                                cross apply (
                                                select T.X.value('local-name(.)', 'nvarchar(max)')
                                            ) as C(Name)
                                cross apply (
                                                select DATA_TYPE from INFORMATION_SCHEMA.COLUMNS where TABLE_NAME ='' + @table + '' and COLUMN_NAME = C.Name 
                                            ) as CType
                            ORDER BY C.Name
                            for xml path(''), type
                        ).value('text()[1]', 'nvarchar(max)')
                        , 1, 1, '')


-- transfrom xml to sql table
DECLARE @SQL nvarchar(max)
SET @SQL =  'select ' + @COLUMNSBYTYPE +
        ' from @x.nodes(''/row'') as T(X)'
exec sp_executesql @SQL, N'@x xml', @x = @xml

Answer 1

您是否在寻找能够轻松完成此任务的应用？如果是，那么您可以尝试Total XML Converter，它可以批量转换xml到sql。

将xml转换为sql表

1 个答案: