我在MySQL数据库中有以下数据：
id value
-- -----
1 7.07
2 1.00
3 4.81
4 1.39
5 1.60
6 9.11
7 6.99
8 1.95
9 1.00
10 1.00
11 1.62
12 1.38
13 1.33
14 1.41
15 3.67
16 3.62
17 2.43
18 3.15
19 57.30
20 1.33
21 1.68
22 6.52
23 2.75
24 2.36
25 2.01
26 2.22
27 5.35
28 2.30
29 1.05
30 24.21
我试图对结果进行排序，计算相同范围内的连续值的数量，如下所示：
value consecutive repetitions
----- -----------------------
7. 1
1. 1
4. 1
1. 2
9. 1
6. 1
1. 7
3. 2
2. 1
3. 1
57. 1
1. 2
6. 1
2. 4
5. 1
2. 1
1. 1
24. 1
所以，正如你所看到的，我基本上想要移除浮点数，按照数字的整数值对数字进行分组，并计算它们连续重复的次数。
我试过这个，但它似乎并没有在MySQL上运行：
SELECT value, COUNT(*)
FROM (select live_records.*,
(row_number() over (order by id) -
row_number() over (partition by value order by id)
) as grp
from live_records
) live_records
group by grp, value;
有什么想法吗？ 谢谢！
答案 0 :(得分：2)
表格结构：
create table test (a int, b float);
插入值：
insert into test values(1,7.07);
insert into test values(2,1.00);
insert into test values(3,4.81);
insert into test values(4,1.39);
insert into test values(5,1.60);
insert into test values(6,9.11);
insert into test values(7,6.99);
insert into test values(8,1.95);
insert into test values(9,1.00);
insert into test values(10,1.00);
insert into test values(11,1.62);
insert into test values(12,1.38);
insert into test values(13,1.33);
insert into test values(14,1.41);
insert into test values(15,3.67);
insert into test values(16,3.62);
insert into test values(17,2.43);
insert into test values(18,3.15);
insert into test values(19,57.30);
insert into test values(20,1.33);
insert into test values(21,1.68);
insert into test values(22,6.52);
insert into test values(23,2.75);
insert into test values(24,2.36);
insert into test values(25,2.01);
insert into test values(26,2.22);
insert into test values(27,5.35);
insert into test values(28,2.30);
insert into test values(29,1.05);
insert into test values(30,24.21);
SQL查询：
set @groupvalue := 0;
set @comparevalue := null;
select groupingvalue, max(value), count(value)
from
(
select if(@comparevalue=floor(b),@groupvalue,@groupvalue := @groupvalue + 1 )
groupingvalue,
@comparevalue := floor(b) as value
from test t
) a
group by groupingvalue
说明：