Question

我正在尝试获取在特定日期之前/之后创建的用户，并且我收到此错误。

“message”：“Argument \”filter \“具有无效值$ filter。\ nIn field \”insertedAfter \“：预期类型\”NaiveDateTime \“，找到\”2018-05-13 \“。”，

错误是有道理的，因为“2018-05-13”不是NativeDateTime ...但是，我认为NativeDateTime应该解析字符串“2018-05-13”。我正在尝试应用我从书中学到的东西但是很难。我还创建了一个自定义日期标量但我基本上遇到了同样的错误。

如何在凤凰和苦艾酒的某个日期之后搜索创建的用户？

query($filter: UserFilter){
  allUsers(filter: $filter){
    id
    firstName
    lastName
  }
}

values
{
  "filter": {
    "insertedAfter": "2018-05-13"
  }
}

Ecto架构，帐户＆gt; user.ex

schema "users" do
  field :avatar_img, :string
  field :email, :string, null: false
  field :fb_token, :string
  field :first_name, :string
  field :google_token, :string
  field :last_name, :string
  field :password, :string, null: false
  field :admin_user_id, :string

  timestamps()
 end

types.ex

 use Absinthe.Schema.Notation
 use Absinthe.Ecto, repo: ElixirBlog.Repo
 import_types Absinthe.Type.Custom

 object :user do
  field :id, non_null(:id)
  field :first_name, non_null(:string)
  field :last_name, non_null(:string)
  field :email, non_null(:string)
  field :password, non_null(:string)
  field :avatar_img, :string
  field :admin_user_id, :string
  field :fb_token, :string
  field :google_token, :string
  field :inserted_at, :naive_datetime
  field :updated_at, :naive_datetime
end

Absinthe架构 schema.ex

use Absinthe.Schema
import_types Elixir.Schema.Types

input_object :user_filter do
  field :id, :integer
  field :first_name, :string
  field :last_name, :string
  field :email, :string
  field :inserted_before, :naive_datetime
  field :inserted_after, :naive_datetime
end

query do
  field :all_users, list_of(:user) do
   arg :filter, :user_filter
   arg :order, type: :sort_order, default_value: :asc
   resolve &ElixirBlogWeb.UsersResolver.all_users/3
  end
end

users_resolver.ex

alias Elixir.Account

def all_users(_root, args, _info) do
 users = Account.list_users(args)
 {:ok, users}
end

account.ex

def list_users(args) do
  args
  |> Enum.reduce(User, fn
    {:order, order}, query ->
    query |> order_by({^order, :first_name})
    {:filter, filter}, query ->
      query |> filter_with(filter)
    end)
  |> Repo.all
end

defp filter_with(query, filter) do
  Enum.reduce(filter, query, fn
    {:id, id}, query ->
      from q in query, where: q.id == ^id
    {:first_name, first_name}, query ->
      from q in query, where: ilike(q.first_name, ^"%#{first_name}%")
    {:last_name, last_name}, query ->
      from q in query, where: ilike(q.last_name, ^"%#{last_name}%")
    {:email, email}, query ->
      from q in query, where: ilike(q.email, ^"%#{email}%")
    {:inserted_before, date}, query ->
      from q in query, where: q.inserted_at <= ^date
    {:inserted_after, date},  query ->
      from q in query, where: q.inserted_at >= ^date
 end)
end

mix.exs

  {:phoenix, "~> 1.3.2"},
  {:phoenix_ecto, "~> 3.2"},
  {:absinthe, "~> 1.4"},
  {:absinthe_plug, "~> 1.4"},
  {:absinthe_ecto, "~> 0.1.3"},

Answer 1

我在:naive_datetime的文档中找不到关于Absinthe的内容。

但我们可以[在Absinthe的代码中找到它]（https://github.com/absinthe-graphql/absinthe/blob/master/lib/absinthe/type/custom.ex#L29）

The DateTime appears in a JSON response as an ISO8601 formatted string.

因此我们可以使用datetime "2018-05-13 00:00:07"。

Elixir，Absinthe如何在苦艾酒日期之后创建用户？

1 个答案: