例如,这是JSON,如下所示。我实际上从亚马逊网站上获取了这个,但我认为这适用于这个问题。
{
"player": {
"username": "user1",
"characteristics": {
"race": "Human",
"class": "Warlock",
"subclass": "Dawnblade",
"power": 300,
"playercountry": "USA"
},
"arsenal": {
"kinetic": {
"name": "Sweet Business",
"type": "Auto Rifle",
"power": 300,
"element": "Kinetic"
},
"energy": {
"name": "MIDA Mini-Tool",
"type": "Submachine Gun",
"power": 300,
"element": "Solar"
},
"power": {
"name": "Play of the Game",
"type": "Grenade Launcher",
"power": 300,
"element": "Arc"
}
},
"armor": {
"head": "Eye of Another World",
"arms": "Philomath Gloves",
"chest": "Philomath Robes",
"leg": "Philomath Boots",
"classitem": "Philomath Bond"
},
"location": {
"map": "Titan",
"waypoint": "The Rig"
}
}
}
我想将此转换为以下并保存为avro。我是新手来编程,因此围绕功能风格包围我的Java背景有点困难。请至少指导我,这样我就可以自己编写代码了。
{
"player.username": "user1",
"player.characteristics.race": "Human",
"player.characteristics.class": "Warlock",
"player.characteristics.subclass": "Dawnblade",
"player.characteristics.power": 300,
"player.characteristics.playercountry": "USA",
"player.arsenal.kinetic.name": "Sweet Business",
"player.arsenal.kinetic.type": "Auto Rifle",
"player.arsenal.kinetic.power": 300,
"player.arsenal.kinetic.element": "Kinetic",
"player.arsenal.energy.name": "MIDA Mini-Tool",
"player.arsenal.energy.type": "Submachine Gun",
"player.arsenal.energy.power": 300,
"player.arsenal.energy.element": "Solar",
"player.arsenal.power.name": "Play of the Game",
"player.arsenal.power.type": "Grenade Launcher",
"player.arsenal.power.power": 300,
"player.arsenal.power.element": "Arc",
"player.armor.head": "Eye of Another World",
"player.armor.arms": "Philomath Gloves",
"player.armor.chest": "Philomath Robes",
"player.armor.leg": "Philomath Boots",
"player.armor.classitem": "Philomath Bond",
"player.location.map": "Titan",
"player.location.waypoint": "The Rig"
}
答案 0 :(得分:0)
它实际上与火花无关,你只需要一个函数将嵌套的json字符串展平为一个新的json字符串。如果您首先拥有RDD [String],则代码示例将是一些代码。
rdd.mapPartitions(ps => ps.map(jsonFlatten))
然后将rdd
转换为dataframe
可以在此处找到样本jsonFlatten
: