我正在准备测试,运行此脚本后有一个警告:
class TestForm(unittest.TestCase):
def setUp(self):
with open('test_json.json') as f:
self.hd = json.load(f)
self.reader = csv.reader(open('test.csv'))
self.result = {}
for row in self.reader:
key = row[0]
self.result[key] = row[1:]
def test_1(self):
self.form = self.hd[0]['Customer'][0]['Information'][0]['Form']
self.exp = self.result['Form1'][0]
self.assertEqual(self.form, self.exp)
def test_2(self):
self.form = self.hd[1]['Customer'][0]['Information'][0]['Form']
self.exp = self.result['Form2'][0]
self.assertEqual(self.form, self.exp)
错误:
.C:\Program Files\Python\3.5.1\lib\unittest\suite.py:107: ResourceWarning: unclosed file <_io.TextIOWrapper name='test.csv' mode='r' encoding='cp1250'>
for index, test in enumerate(self):
脚本已完成,但此错误很奇怪。我观察到只有当这部分在setUp
函数中时才会出现:
with open('test_json.json') as f:
self.hd = json.load(f)
self.reader = csv.reader(open('test.csv'))
self.result = {}
for row in self.reader:
key = row[0]
self.result[key] = row[1:]
当我在TestForm
之外使用它时,脚本中没有警告。我应该将它移回class TestForm
之外,还是在不同的档案中进行?
答案 0 :(得分:1)
此代码打开一个CSV文件并永久保持打开状态:
self.reader = csv.reader(open('test.csv'))
这是“正确”的方法:
with open('test.csv') as csv_file:
self.reader = csv.reader(csv_file)
# use the file
# the file is closed here, when the context is closed
另一种方法是“手动”打开和关闭:
csv_file = open('test.csv')
self.reader = csv.reader(csv_file)
# use the file
# when you are done, close the file:
csv_file.close()
您似乎永远不会在self.reader
之后使用setUp
,所以这似乎是您案例中的最佳解决方案:
def setUp(self):
with open('test.csv') as csv_file:
reader = csv.reader(csv_file)
self.result = {}
for row in reader:
key = row[0]
self.result[key] = row[1:]
# csv_file closes here; reader is not any longer available either