Question

此示例使用Tolkien-Arda示例数据库和批处理模式。以下脚本

LET $1 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='hildigrimTook';
LET $2 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='adalgrimTook';
SELECT INTERSECT($1, $2).size();

返回7（我添加了额外内容，我认为默认值为2）

但是，当在完整脚本中使用时，size（）似乎返回0，因此它总是创建一个新边

LET $1 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='hildigrimTook';
LET $2 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='adalgrimTook';
LET $3 = SELECT INTERSECT($1, $2);
LET $4 = CREATE EDGE Begets FROM (SELECT FROM Creature WHERE uniquename='hildigrimTook') TO (SELECT FROM Creature WHERE uniquename='adalgrimTook');
IF($3.size() > 0) {
    return 'Already present';
}
IF($3.size() == 0) {
    return $4;
}

此脚本应检查hildigrimTook和adalgrimTook之间的边缘，如果它尚不存在则创建边缘。似乎INTERSECT（$ 1，$ 2）.size（）在从IF（）语句内部调用时返回0，但在用作SELECT的一部分时返回7.

我试过了

LET $1 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='hildigrimTook';
LET $2 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='adalgrimTook';
LET $3 = SELECT INTERSECT($1, $2);
SELECT $3.size()

但这也回归0.我也做了

LET $1 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='hildigrimTook';
LET $2 = SELECT expand(bothE(Begets)) FROM Creature WHERE uniquename='adalgrimTook';
LET $3 = SELECT INTERSECT($1, $2).size();
SELECT $3;

按预期返回7但是当我尝试在IF语句中运行它时，我得到一个Java空指针异常

IF($3 > 0) {
    return 'Already present';
}
IF($3 == 0) {
    return $4;
}

预期的输出将是脚本返回“已经存在”或新创建的边缘的@rid。帮助赞赏，我已经尝试了我能想到的每一种方式，文档中没有详细介绍IF。

Orientdb size（）从IF（）内部返回不同的结果

0 个答案: