处理java中的.csv文件(新手级别)

时间:2018-05-14 15:53:57

标签: java

我正在尝试从.csv文件中获取某些数据并将其打印到输出。 String类型没有带来任何问题,但处理int制作让我感到奇怪。我试图从文件中创建一个数组并从中提取所需的元素,但代码根本不会编译。

package readcvs;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;

public class ReadCVS {
    public static void main(String[] args) { 
        ReadCVS obj = new ReadCVS();
        obj.run();
    }

  public void run() {

        String csvFile = "/Users/hobbit/Desktop/E0.csv";
        BufferedReader br = null;
        String line = "";
        String csvSplitBy = ",";
         try {
            br = new BufferedReader(new FileReader(csvFile));
            while ((line = br.readLine()) != null) {
                // comma is used as a separator
                String[] tie = line.split(csvSplitBy);
                System.out.println(tie[2] + " vs " + tie[3]);
                String[] ref = line.split(csvSplitBy);
                System.out.println ("Referee: " + ref[10]);

                int digit = Integer.valueOf(line);
                //convert String to integer

                int[] shotsarr = new int[digit];
                System.out.println("Home team shots: " + shotsarr[11]);
            }
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if (br != null) {
                try {
                    br.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }                        
            }
        }
    }
}

0 个答案:

没有答案