Question

如何在React中为组件制作渐变背景，如下图所示 Gradient of same color

与<Box color="orange"><Box>类似，此组件的样式将类似于

backgroundColor="this.props.color"

现在我只想传递颜色道具，我不想传递两种颜色，颜色也是十六进制。

Answer 1

您仍然需要以某种方式指定第二种颜色。您可以传入第一种颜色，然后可能计算组件中的第二种颜色。在这里，我将第二种颜色转换为比输入颜色暗20％。

您可以根据具体用例的需要调整逻辑。

＆＃13;

{
  "name": "influx-archiver2",
  "version": "0.0.16-SNAPSHOT",
  "license": "MIT",
  "scripts": {
    "ng": "ng",
    "start": "ng serve",
    "build": "ng build",
    "test": "ng test",
    "lint": "ng lint",
    "e2e": "protractor",
    "pree2e": "webdriver-manager update --standalone false --gecko false",
    "jenkins-build": "echo \"placeholder for your jenkins-build script\""
  },
  "private": true,
  "dependencies": {
    "@angular/animations": "4.3.0",
    "@angular/cdk": "^5.2.4",
    "@angular/common": "4.3.0",
    "@angular/compiler": "4.3.0",
    "@angular/core": "4.3.0",
    "@angular/forms": "4.3.0",
    "@angular/http": "4.3.0",
    "@angular/material": "^5.2.5",
    "@angular/platform-browser": "4.3.0",
    "@angular/platform-browser-dynamic": "4.3.0",
    "@angular/platform-server": "4.3.0",
    "@angular/router": "4.3.0",
    "@swimlane/ngx-datatable": "^10.2.3",
    "bootstrap": "^3.3.7",
    "core-js": "^2.5.1",
    "font-awesome": "^4.7.0",
    "hammerjs": "^2.0.8",
    "hover.css": "^2.2.1",
    "jquery": "^3.2.1",
    "ng-spin-kit": "^5.1.1",
    "ng2-filter-pipe": "^0.1.10",
    "ngx-bootstrap": "1.9.1",
    "ngx-dropdown": "0.0.22",
    "rxjs": "^5.4.3",
    "tinymce": "^4.6.6",
    "underscore": "^1.8.3",
    "zone.js": "^0.8.17"
  },
  "devDependencies": {
    "@angular/cli": "^1.4.9",
    "@angular/compiler-cli": "4.3.0",
    "@angular/language-service": "4.3.0",
    "@types/jasmine": "2.5.54",
    "@types/jquery": "^3.2.12",
    "@types/node": "8.0.26",
    "codelyzer": "3.1.2",
    "jasmine-core": "2.8.0",
    "jasmine-spec-reporter": "4.2.1",
    "karma": "1.7.1",
    "karma-chrome-launcher": "^2.2.0",
    "karma-cli": "^1.0.1",
    "karma-jasmine": "^1.1.0",
    "karma-remap-istanbul": "0.6.0",
    "protractor": "5.1.2",
    "ts-node": "3.3.0",
    "tslint": "5.7.0",
    "typescript": "2.5.2",
    "webpack": "^3.8.1"
  },
  "spar": {
    "name": "influx-archiver2",
    "rootPath": "./dist"
  }
}

＆＃13;

class App extends React.Component {
  render() {
    return (
      <Box color1="#FFA500" />
    );
  }
}

const Box = ({color1}) => {
  const rgb = [color1.substring(1,3), color1.substring(3,5), color1.substring(5,7)];
  const color2 = `rgb(${rgb.map(c => (parseInt(c, 16) * 0.8)).join()})`;
  return (
    <div className="box" style={{background: `linear-gradient(${color1}, ${color2})`}} />
  );
}

ReactDOM.render(<App />, document.getElementById("app"));

＆＃13;

.box {
  width: 100px;
  height: 100px;
}

＆＃13;

Answer 2

为什么不将渐变用作background-color上方的图层来实现此目的：

.box{
  height:200px;
  width:200px;
  background:linear-gradient(rgba(250,0,0,0.5),transparent);
  background-color:orange /*this your primary color*/
}

<div class="box">
</div>

如何使用1种颜色制作React渐变？

2 个答案: