我一般都是API的新手。我正在尝试学习如何使用Google GeoCode API从用户输入的邮政编码中获取县。我正在使用.NET Core MVC
可以使用以下URL查看示例有效内容: http://maps.googleapis.com/maps/api/geocode/json?address=77379&sensor=true
产生有效载荷:
{
"results" : [
{
"address_components" : [
{
"long_name" : "77379",
"short_name" : "77379",
"types" : [ "postal_code" ]
},
{
"long_name" : "Spring",
"short_name" : "Spring",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Harris County",
"short_name" : "Harris County",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "Texas",
"short_name" : "TX",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United States",
"short_name" : "US",
"types" : [ "country", "political" ]
}
],
"formatted_address" : "Spring, TX 77379, USA",
"geometry" : {
"bounds" : {
"northeast" : {
"lat" : 30.088189,
"lng" : -95.47364999999999
},
"southwest" : {
"lat" : 29.9871611,
"lng" : -95.5887879
}
},
"location" : {
"lat" : 30.0314279,
"lng" : -95.5302337
},
"location_type" : "APPROXIMATE",
"viewport" : {
"northeast" : {
"lat" : 30.088189,
"lng" : -95.47364999999999
},
"southwest" : {
"lat" : 29.9871611,
"lng" : -95.5887879
}
}
},
"place_id" : "ChIJtZcGtDLNQIYRtGE9AgmSOPQ",
"postcode_localities" : [ "Klein", "Spring" ],
"types" : [ "postal_code" ]
}
],
"status" : "OK"
}
例如,我想从上面的url JSON结果中获取字符串“Harris County”。
在我的模型中,我有:
public class GoogleAddress
{
public List<Result> results;
}
[DataContract]
public class Result
{
[DataMember(Name = "long_name")]
public string long_name { get; set; }
[DataMember(Name = "short_name")]
public string short_name { get; set; }
[DataMember(Name = "types")]
public string types { get; set; }
}
在我的控制器中,我的方法中有以下内容:
//zip to be passed as a parameter in my method later, hardcoded here for testing
string zip = "77379";
string county = "";
var serializer = new DataContractJsonSerializer(typeof(GoogleAddress));
//example url: http://maps.googleapis.com/maps/api/geocode/json?address=77379&sensor=true
string url = "http://maps.googleapis.com/maps/api/geocode/json?address=" + zip + "&sensor=true";
var client = new HttpClient();
var streamTask = client.GetStreamAsync(url);
var address = (GoogleAddress)serializer.ReadObject(await streamTask);
var result = address.results;
//how do I get the county from the result?
return View(county);
我的模型应该如何设置以匹配有效负载?如何从有效负载中获取县名?
答案 0 :(得分:0)
考虑使用像Json.Net这样的框架。使用它,您可以动态地解析您的json响应,并只获取那些对您有用的部分:
var jsonResult = "some json from google api";
dynamic jsonObject = JObject.Parse(jsonResult);
var long_name = jsonObject.results[0].address_components[2].long_name;
var short_name = jsonObject.results[0].address_components[2].short_name;
如果您想使用谷歌返回的整个数据集,您可以创建一个合适的类结构(这可以通过使用json2csharp或Visual Studio Paste Special functionality等工具自动生成)反序列化你的json结果:
班级结构
public class AddressComponent
{
public string long_name { get; set; }
public string short_name { get; set; }
public List<string> types { get; set; }
}
public class Northeast
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Southwest
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Bounds
{
public Northeast northeast { get; set; }
public Southwest southwest { get; set; }
}
public class Location
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Northeast2
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Southwest2
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Viewport
{
public Northeast2 northeast { get; set; }
public Southwest2 southwest { get; set; }
}
public class Geometry
{
public Bounds bounds { get; set; }
public Location location { get; set; }
public string location_type { get; set; }
public Viewport viewport { get; set; }
}
public class Result
{
public List<AddressComponent> address_components { get; set; }
public string formatted_address { get; set; }
public Geometry geometry { get; set; }
public string place_id { get; set; }
public List<string> postcode_localities { get; set; }
public List<string> types { get; set; }
}
public class RootObject
{
public List<Result> results { get; set; }
public string status { get; set; }
}
反序列化json
var data = JsonConvert.DeserializeObject<RootObject>(jsonResult);
var long_name = data.results[0].address_components[2].long_name;
var short_name = data.results[0].address_components[2].short_name;
修改强>
完整示例:
string zip = "77379";
string url = "http://maps.googleapis.com/maps/api/geocode/json?address=" + zip + "&sensor=true";
var client = new HttpClient();
// 'using' forces proper cleanup after finishing the operation
using(var response = await client.GetAsync(url))
{
if(response.IsSuccessStatusCode)
{
var jsonResult = await response.Content.ReadAsStringAsync();
dynamic jsonObject = JObject.Parse(jsonResult);
// Consider doing some validation first to be sure that 'results' and 'address_components' contains any elements to avoid exceptions
var long_name = jsonObject.results[0].address_components[2].long_name;
var short_name = jsonObject.results[0].address_components[2].short_name;
}
}