Question

在Django + Wagtail项目中，我有一个自定义方法，我从模型save()方法调用。它工作 - 但每次我通过wagtail管理界面保存一个实例，这个方法被调用两次 - 为什么？

# models.py
from wagtail.core.models import Page

class ArticlePage(Page):

    def my_method(self):
        print('I will be printed twice on save...')

    def save(self, *args, **kwargs):
        self.my_method() 
        super().save(*args, **kwargs)

按照Håken Lid的建议使用traceback.print_stack我发现该方法首先通过

进行调用

  File ".../.venv/lib/python3.6/site-packages/wagtail/admin/views/pages.py", line 336, in edit
    submitted_for_moderation=is_submitting,
  File ".../.venv/lib/python3.6/site-packages/wagtail/core/models.py", line 653, in save_revision
    self.save(update_fields=update_fields)

和第二次通过

  File ".../.venv/lib/python3.6/site-packages/wagtail/admin/views/pages.py", line 343, in edit
    revision.publish()
  File ".../.venv/lib/python3.6/site-packages/wagtail/core/models.py", line 1498, in publish
    page.save()

但即使有了这些信息，我也不知道如何只在第二次保存时触发我的方法...

ENV：
Django 2.0.4
Wagtail 2.0.1

Answer 1

如果您想在页面发布上执行某些操作，可以使用以下page_published信号：

    from django.dispatch import receiver
    from wagtail.core.signals import page_published
    @receiver(page_published)
    def do_stuff_on_page_published(instance, **kwargs):
        print('=======================',instance,kwargs)

如果是保存，您还可以检查update_fields中的kwargs参数：

    def save(self, *args, **kwargs):
        if kwargs.get('update_fields'):
            pass # save not called from publish
            # do_stuff_on_save()
        else:
            pass
            # do_stuff_on_publish()
        return super().save(*args, **kwargs)

有关wagtail信号代码的详细信息，请访问此link 这是官方文档 http://docs.wagtail.io/en/v1.7/reference/signals.html

自定义wagtail页面模型保存方法调用两次

1 个答案: