我有一个json文件,格式如下:
{
"HDRDTL":["SRNO","STK_IDN","CERTIMG"],
"PKTDTL":[
{"SRNO":"2814","STK_IDN":"1001101259","CERTIMG":"6262941723"},
{"SRNO":"2815","STK_IDN":"1001101269","CERTIMG":"6262941726"},
{"SRNO":"2816","STK_IDN":"1001101279","CERTIMG":"6262941729"}
],
"IMGTTL":
["CERTIMG","ARRIMG"],
"IMGDTL":{"CERTIMG":"CRd6z2uq3gvx7kk","ARRIMG":"ASd6z2uq3gvx7kk"}
}
“PKTDTL”数组是我需要转换为csv的部分。 我怎样才能在C#中实现这个目标?
注意,作为一个例子,我在“PKTDTL”中只有3个项目,真正的json文件有数千行({“SRNO”...})并且很大。
我写了下面的代码但是没有用。请参阅代码中注释的错误消息。
问题
你有更好的/替代方法
public static void ConvertJsonToCSV(string InFile)
{
string OutFile=InFile.Replace("json","csv");
StreamReader sInFile = new StreamReader(InFile);
StreamWriter sOutFile = new StreamWriter(OutFile);
using (sInFile)
{
string sJson = sInFile.ReadToEnd();
//*************************************************************
// the below line failed, error message: unexpected json token
// when reading datatable, expected startArray, got StartObject.
//**************************************************************
DataTable dt = JsonConvert.DeserializeObject<DataTable>(sJson);
//DataTable dt = JsonConvert.DeserializeAnonymousType(sJson, new { Makes = default(DataTable) }).Makes;
var sb = new StringBuilder();
string[] columnNames = (from dc in dt.Columns.Cast<DataColumn>()
select dc.ColumnName).ToArray();
sb.AppendLine(string.Join(",", columnNames));
foreach (DataRow dr in dt.Rows)
{
foreach (object field in dr.ItemArray)
{
sb.Append(field.ToString().Replace(",", "") + ",");
}
sb.Replace(",", "\n", sb.Length - 1, 1);
}
sOutFile.Write(sb.ToString());
sOutFile.Close();
sInFile.Close();
}
}
答案 0 :(得分:1)
我发现自己处于类似情况。这就是我做的。首先我创建了一个JObject(使用Newtonsoft.Json.Linq),让我们考虑一下你的json是一个名为“strJSON”的字符串变量。
JObject jsonObj= JObject.parse(strJSON);
JObject PKTDL=jsonObj["PKTDTL"] as JObject;
IList<string> keys = PKTDL.Properties().Select(p => p.Name).ToList(); // this gives column names
StringBuilder sb=new StringBuilder();
string headers="";
foreach(string key in keys)
{
headers+=","+key;
}
sb.AppendLine(headers.TrimStart(','));
foreach(JObject j in jsonObj["PKTDTL"]) //if jobject doesnt work try "JToken j"
{
string values="";
foreach(string key in keys)
{
values+=","+jsonObj["PKTDTL"][key];
}
sb.AppendLine(values.TrimStart(','));
}
File.WriteAllText(filePath, sb.ToString());
然后将sb保存为csv
答案 1 :(得分:1)
使用Cinchoo ETL - 一个开源库,您可以使用几行代码轻松完成转换
string json = @"{
""HDRDTL"":[""SRNO"",""STK_IDN"",""CERTIMG""],
""PKTDTL"":[
{""SRNO"":""2814"",""STK_IDN"":""1001101259"",""CERTIMG"":""6262941723""},
{""SRNO"":""2815"",""STK_IDN"":""1001101269"",""CERTIMG"":""6262941726""},
{""SRNO"":""2816"",""STK_IDN"":""1001101279"",""CERTIMG"":""6262941729""}
],
""IMGTTL"":
[""CERTIMG"",""ARRIMG""],
""IMGDTL"":{""CERTIMG"":""CRd6z2uq3gvx7kk"",""ARRIMG"":""ASd6z2uq3gvx7kk""}
}";
StringBuilder sb = new StringBuilder();
using (var p = ChoJSONReader.LoadText(json).WithJSONPath("$..PKTDTL")
)
{
using (var w = new ChoCSVWriter(sb)
.WithFirstLineHeader()
)
w.Write(p);
}
Console.WriteLine(sb.ToString());
输出:
SRNO,STK_IDN,CERTIMG
2814,1001101259,6262941723
2815,1001101269,6262941726
2816,1001101279,6262941729
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答案 2 :(得分:0)
与duplicate类似的问题(请参见那里的JsonToCsv(string,string)方法)。如果您已经在使用NewtonSoft Json.NET和CsvHelper,则可以在ExpandoObject的帮助下进行类似的转换。
var jsonText = @"{
""HDRDTL"":[""SRNO"",""STK_IDN"",""CERTIMG""],
""PKTDTL"":[
{""SRNO"":""2814"",""STK_IDN"":""1001101259"",""CERTIMG"":""6262941723""},
{""SRNO"":""2815"",""STK_IDN"":""1001101269"",""CERTIMG"":""6262941726""},
{""SRNO"":""2816"",""STK_IDN"":""1001101279"",""CERTIMG"":""6262941729""}
],
""IMGTTL"":
[""CERTIMG"",""ARRIMG""],
""IMGDTL"":{""CERTIMG"":""CRd6z2uq3gvx7kk"",""ARRIMG"":""ASd6z2uq3gvx7kk""}
}";
var jtoken = JObject.Parse(jsonText).SelectToken("$..PKTDTL");
var expandos = jtoken.ToObject<ExpandoObject[]>();
string csvText;
using (var writer = new StringWriter())
{
using (var csv = new CsvWriter(writer))
{
csv.WriteRecords(expandos as IEnumerable<dynamic>);
}
csvText = writer.ToString();
}
Console.WriteLine(csvText);