当我访问登录功能并返回功能错误时跳过SecureStore

Question

当我调用loginUser函数时，它假设访问SecureStore函数，而是返回axios.post方法。

知道这里出了什么问题吗？

import { SecureStore } from 'expo';

export function loginUser(email, password) {
  return function (dispatch) {
    return axios.post(SIGNIN_URL, { email, password }).then((response) => {
      var { user_id, token } = response.data;
      Expo.SecureStore.setItemAsync(user_id, password, options).then(function() {
        dispatch(authUser(user_id));
        console.log('I am in')
      }).catch((error) => {
        console.log('Its an error')
        dispatch(addAlert("Could not log in."));
      });
    }).catch((error) => {
      dispatch(addAlert("Could not log in."));
    });
  };
}

Answer 1

问题在于您构建承诺链的方式。

const promiseOne = new Promise((resolve, reject) => {
  resolve('p1')
})

const promiseTwo = new Promise((resolve, reject) => {
  resolve('p2')
})


promiseOne.then(
    (res) => {
      console.log('res', res)
      return promiseTwo
    })
  .then((res2) => {
    console.log('res2', res2)
  })

基本上，您需要将通话返回到Expo