我很困惑如何继续获取Test1的所有其他信息索引的结果,所以如果Test1为true,即使Test2和Test3为null,它也将基于Test1继续打印
let info = ["Test1", "Test2", "Test3"];
isInfoAviable= (email) => {
payload.info = info
return axios.post(url, payload, axiosConfig).then((response) => {
return response.data.isAvailable ? true : null
}).catch((error) => {
console.log(error);
});
}
for (info of infos) {
isInfoAviable(info).then((res) => {
console.log(res) // If Test1 returns true, it'll true even if Test2 is null, why?
})
}