Question

我有一个在几个页面上相同的联系表单，所以我有一个php脚本，由具有联系表单的所有页面调用。脚本工作正常，处理recaptcha，发送电子邮件，一切都很好。但是，每次运行时，在告知用户邮件发送成功的警报之后，它会打开一个空白页面，其中包含php脚本的URL。我只希望页面保持原状 - 显示成功（或失败）警报，用户点击确定，并且他正盯着同一页面。这是以下形式：

                    <div class="col-md-7">
                        <h2>Contact Us</h2> Got a question ? Feedback? Awesome!
                        <form class="mt-4 mt-md-0" role="form" action="/php/mail.php" method="post" >
                            <div class="form-group">
                                <label for="name" class="sr-only control-label">Name</label>
                                <input class="form-control bg-faded-4" id="form_name" type="text" name="name" placeholder="Please enter your name *" required="required" data-error="Name is required.">
                                <div class="help-block with-errors"></div>
                            </div>
                            <div class="form-group">
                                <label for="email" class="sr-only control-label">Email</label>
                                <input class="form-control bg-faded-4" id="form_email" type="email" name="email" class="form-control" placeholder="Please enter your email *" required="required" data-error="Valid email is required.">
                                <div class="help-block with-errors"></div>
                            </div>
                            <div class="form-group">
                                <label for="message" class="sr-only control-label">Message</label>
                                <textarea class="form-control bg-faded-4" id="form_message" name="message" placeholder="Message for me *" rows="4" required="required" data-error="Please,leave us a message."></textarea>
                                <div class="help-block with-errors"></div>
                            </div>
                            <div class="form-group">
                            <div class="row" style="margin-bottom:30px;">
                                <span class="msg-error error"></span>
                                <div class="g-recaptcha" data-sitekey="<MY_SITE_KEY>" style="padding-left: 15px"></div>                                    
                            </div>
                            </div>
                            <button type="submit" class="btn btn-secondary btn-sm mt-2" name="submit" id="submit">Send Message</button>
                        </form>
                    </div>
                </div>

这是php脚本：

<?php
  $errName = "";
  $errEmail = "";
  $errMessage = "";
  $name = $_POST['name'];
  $email = $_POST['email'];
  $message = $_POST['message'];
  $from = 'myform@mysite.com'; 
  $to = 'myemail@gmail.com'; 
  $subject = 'Message from Contact Form ';

  $body = "From: $name\n E-Mail: $email\n Message:\n $message";

// Check if name has been entered
if (!$_POST['name']) {
    $errName = 'Please enter your name';
}
else
  $sender_name = stripslashes($_POST["name"]);

// Check if email has been entered and is valid
if (!$_POST['email'] || !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL))     {
    $errEmail = 'Please enter a valid email address';
}
else
  $sender_email = stripslashes($_POST["email"]);

//Check if message has been entered
if (!$_POST['message']) {
    $errMessage = 'Please enter your message';
}
else
  $sender_message = stripslashes($_POST["message"]);

  $response = $_POST["g-recaptcha-response"];
    $url = 'https://www.google.com/recaptcha/api/siteverify';
    $data = array(
        'secret' => '<MY_SECRET_KEY>',
        'response' => $_POST["g-recaptcha-response"]
    );
    $options = array(
        'http' => array (
        'method' => 'POST',
        'content' => http_build_query($data)
        )
    );
    $context  = stream_context_create($options);
    $verify = file_get_contents($url, false, $context);
    $captcha_success=json_decode($verify);


   // If there are no errors, send the email
    if ($captcha_success->success==false) {
        echo "<p>You are a bot! Go away!</p>";
    } else if ( ($errName != "") ) {
      echo "<script type='text/javascript'>alert('Please enter your name.');    </script>";
    } else if ($errEmail != "") {
      echo "<script type='text/javascript'>alert('You must enter a valid email address. Please try again.');</script>";
    } else if ( $errMessage != "") {
      echo "<script type='text/javascript'>alert('You must enter some message     text. Please try again.');</script>";
    } else {


      // All the neccessary headers for the email.
      $headers = array('Content-Type: text/plain; charset="UTF-8";',
          'From: ' . $from,
          'Reply-To: ' . $from,
          'Return-Path: ' . $from,
      );

      // Send email
      $mailResponse = mail($to, $subject, $message, implode("\n", $headers));
      if ( $mailResponse == 1 ) {
        echo "<script type='text/javascript'>alert('We\'ll be in touch!');    </script>";
      } else {
        echo "<script type='text/javascript'>alert('Error sending message. Please try again.');</script>"; 
      }
    }
 ?>

我确定这是非常丑陋的PHP代码，并没有真正完成很多PHP编程。但我真正的问题是这个空白窗口在php文件处理表单后显示 - 我该如何阻止它？

感谢.....

所以php脚本的最后一行现在是：

header('Location:http://sq36.cawgcap.org');

但这就是我所看到的。在点击“发送”之前：并在表单处理完毕后：

只要我在警报上点击确定，我就会盯着一个空白页面，地址栏显示php脚本的位置。

Answer 1

只需将用户重定向到其他某个页面即可。

使用header()功能。

当脚本结束时，只需将用户重定向到其他某个页面，例如可能包含感谢信息的thanks.php或mail_sent_successfully.php。

通过在php中使用header() function来实现。

像这样使用

header('Location: mail_sent.php');

因此，添加此行，用户将重定向到mail_sent.php页面。

Answer 2

您可以使用 location.href 重定向用户。因此，在提醒代码后添加： location.href="{url_of_your_form_page}"; 。

您应该避免使用标头功能，因为它会向浏览器发送http位置标头。它将导致浏览器重定向到URL而不显示警告弹出窗口。

从打开新页面停止表单发布php脚本

2 个答案: