Question

我是postgres的新手，我正在尝试创建一个查询，以确定从今天开始的6个月之前的哪个月。另外，我想用西班牙语显示这个月的名字。

例如：今天的月份是“五月”，六个月前是“十一月”，所以我想用西班牙语'Noviembre'显示这个月的名字。

这就是我尝试这样做但它只显示空行：

    select 
( 
    case 
    when to_char(current_date-interval '6 Month','Month')='January' then 'Enero'
    when to_char(current_date-interval '6 Month','Month')='February' then 'Febrero'
    when to_char(current_date-interval '6 Month','Month')='March' then 'Marzo'
    when to_char(current_date-interval '6 Month','Month')='April' then 'Abril'  
    when to_char(current_date-interval '6 Month','Month')='May' then 'May'
    when to_char(current_date-interval '6 Month','Month')='June' then 'Junio'
    when to_char(current_date-interval '6 Month','Month')='July' then 'Junio'
    when to_char(current_date-interval '6 Month','Month')='August' then 'Agosto'
    when to_char(current_date-interval '6 Month','Month')='September' then 'Septiembre' 
    when to_char(current_date-interval '6 Month','Month')='October' then 'Octubre'
    when to_char(current_date-interval '6 Month','Month')='November' then 'Noviembre'
    when to_char(current_date-interval '6 Month','Month')='December' then 'Diciembre'
    end
) as "Hace 6 Meses"
from "recibopagoderechoslaborales";

Answer 1

您只需为您的客户调整lc_time：

so=# set lc_time = 'es_ES';
SET
so=# select to_char(now() - '6 month'::interval,'TMMonth');
  to_char
-----------
 Noviembre
(1 row)

未对其进行本地化：

so=# set lc_time to default ;
SET
so=# select to_char(now() - '6 month'::interval,'TMMonth');
 to_char
----------
 November
(1 row)

知道哪个月是6个月前，并以西班牙语显示名称

1 个答案: