Question

我是c ++的新手，我需要使用我的函数来存储多个用户输入，然后打印多个用户输入。但是，我的代码只做一个用户输入。我应该将它存储在一个数组中吗？这是一个不言自明的代码，所以你可以跳到底部寻找＆＃34; ?? storeinvariable ??＆＃34;

#include <iostream>

using namespace std;

// Will display all bids
void displayBid(string &bidTitle, string &fundPerson, string &vehicleId, float &bidAmount)
{
cout << "Title: " << bidTitle << endl;
cout << "Fund: " << fundPerson << endl;
cout << "Vehicle: " << vehicleId << endl;
cout << "Bid Amount: " << bidAmount << endl;
}

// Ask the user for title, person, vehicleId, amount
void getBid(string &bidTitle, string &fundPerson, string &vehicleId, float &bidAmount)
{
cout << "Enter Title: ";
cin.ignore();
getline(cin, bidTitle);
cout << "Enter Fund";
cin.ignore();
getline(cin, fundPerson);
cout << "Enter Vehicle ID: ";
cin.ignore();
getline(cin, vehicleId);
cout << "Enter Bid Amount: ";
cin.ignore();
cin >> bidAmount;
}

// Loops through adding bids or displaying bids
main(void)
{
  string title, person, id;
  title = "";
  person = "";
  id = "";
  float amount;
  amount = 0.0;

  int choice = 0;
    while (choice != 9) {
        cout << "Menu:" << endl;
        cout << "  1. Enter Bid" << endl;
        cout << "  2. Display Bid" << endl;
        cout << "  9. Exit" << endl;
        cout << "Enter choice: ";
        cin >> choice;

        switch (choice) {
            case 1:
                ??storeinvariable?? = getBid(title, person, id, amount);
                break;
            case 2:
                // display variable??
                displayBid(title, person, id, amount);
                 break;
        }
    }

    cout << "Good bye." << endl;

  return 1;
}

Answer 1

您可以使用数组。但是，它必须包含两种不同的数据类型。您可以创建void* s的数组或向量，但这不是最佳解决方案。

您可以创建自己的类型（可能是struct）来存储用户输入的数据，如下所示：

typedef struct {
    std::string bidTitle;
    std::string fundPerson;
    std::string vehicleId;
    float bidAmount;
} Bid;

一旦您定义了struct，就可以让您的函数使用此数据类型。

如何存储多个用户输入，然后在C ++中显示它们

1 个答案: