xQuery函数返回值未显示

时间:2018-05-12 15:14:22

标签: sql xml database xquery basex

我正在尝试完成一个关于使用BaseX GUI和mondial数据库查找有关过境数量最远的国家(-ies)的学校作业问题。我用BFS编写了一个递归函数来完成它。查询应返回一组与输入国家最远的国家/地区名称。

当我打电话给下面这个函数找到最遥远的尼加拉瓜国家时,应该返回一些国家名称,包括“加拿大”和“阿根廷”。

let $return-list := local:reachable-far($country[name="Nicaragua"])
return $return-list/country/name

但是,我的回报价格只有加拿大,但阿根廷或苏里南没有其他国家。

<name>Canada</name>

我尝试通过调用

来调试查询
let $return-list := local:reachable-far($country[name="Nicaragua"])
return $return-list/country[name="Argentina"]/name

返回值为

<name>Argentina</name>
我认为这意味着阿根廷(和其他国家)的回报价值但不知何故不显示。我的代码在这里出了什么问题?完整的功能声明粘贴在下面。

declare variable $mondial := doc("D:/mondial.xml")/mondial;
declare variable $country := $mondial/country;

declare function local:reachable-far($curr)
{
  if ($curr = ()) then ()

  else
  (
    local:reachable-bfsl($curr, $curr, $curr, $curr, 0)
  )
};

declare function local:reachable-bfsl($queue, $seen, $lastoflevel, $currlevel, $depth)
{
  (:return current level if stack is empty (should never happen):)
  if (empty($queue)) then (<row>{$currlevel} <depth>{$depth}</depth></row>)

  else
  (
    let $curr := $queue[1]
    let $neighbors-all := $curr/border/@country
    let $neighbors-code := $neighbors-all[not(.=$seen/@car_code)]
    let $neighbors := $country[@car_code = $neighbors-code]

    (:if current country is not the last of level, continue with current level:)
    return if ($curr/@car_code != $lastoflevel/@car_code)
    then
    (
      local:reachable-bfsl(($queue[position()>1], $neighbors),
                           ($seen, $neighbors),
                           $lastoflevel,
                           $currlevel union $curr,
                           $depth)
    )

    (:if current country is the last of level:)
    else
    (
      (:current contury has searchable neighbors or stack is not empty after popping:)
      if (not(empty($neighbors)) or not(empty($queue[position()>1])))
      then
      ( (:clear current level, continue next level, update last of level to last in stack, depth++:)
        local:reachable-bfsl(($queue[position()>1], $neighbors),
                             ($seen, $neighbors),
                             ($queue[position()>1], $neighbors)[last()],
                             (),
                             $depth + 1)
      )

      (:current country does not have searchable neighbors and stack is empty after popping:)
      else
      (
        <row>{trace($currlevel union $curr)} <depth>{$depth}</depth></row>
      )
    )
  )
};


let $return-list := local:reachable-far($country[name="Nicaragua"])
return $return-list/country/name

1 个答案:

答案 0 :(得分:0)

在BaseX 9.0.1(当前版本,可能是您正在使用的版本)中,节点ID排序算法有一个小错误。 BaseX 9.0或最新快照(http://files.basex.org/releases/latest/)应该产生预期的结果。 BaseX 9.0.2将于2018年5月底上市。