Question

输入

{
  "apps": [
    {
      "name": "whatever1",
      "id": "ID1"
    },
    {
      "name": "whatever2",
      "id": "ID2",
      "dep": [
        "a.jar"
      ]
    },
    {
      "name": "whatever3",
      "id": "ID3",
      "dep": [
        "a.jar",
        "b.jar"
      ]
    }
  ]
}

输出

{
  "apps": [
    {
      "name": "whatever1",
      "id": "ID1",
      "dep": [
        "b.jar"
      ]
    },
    {
      "name": "whatever2",
      "id": "ID2",
      "dep": [
        "a.jar",
        "b.jar"
      ]
    },
    {
      "name": "whatever3",
      "id": "ID3",
      "dep": [
        "a.jar",
        "b.jar"
      ]
    }
  ]
}

在上面的例子中

whatever1没有dep，因此请创建一个。
whatever2有dep且没有b.jar，因此请添加b.jar
whatever3有dep b.jar而且# add blindly, whatever3 is not right cat dep.json | jq '.apps[].dep += ["b.jar"]' # missed one level and whatever3 is gone. cat dep.json | jq '.apps | map(select(.dep == null or (.dep | contains(["b.jar"]) | not)))[] | .dep += ["b.jar"]'未受影响。

我的尝试。

{{1}}

Answer 1

为了清楚起见，让我们定义一个辅助函数来执行核心任务：

# It is assumed that the input is an object
# that either does not have the specified key or
# that it is array-valued
def ensure_has($key; $value):
  if has($key) and (.[$key] | index($value)) then .
  else .[$key] += [$value]
  end ;

现在可以直接完成任务：

.apps |= map(ensure_has("dep"; "b.jar"))

或者......

.apps[] |= ensure_has("dep"; "b.jar")

Answer 2

经过一些试验和错误后，看起来这是一种方法。

cat dep.json | jq '.apps[].dep |= (. + ["b.jar"] | unique)'

如果列表为空，如何将元素添加到列表中时，如何创建一个元素？

2 个答案:

或者......