我需要利用C ++的指向成员的指针功能来使函数访问子结构的成员。请注意,函数必须操作的对象对调用者不可见。
我已将其减少到以下玩具问题(C ++ 14或更高版本):
#include <iostream>
struct SubStruct {
int c;
};
struct MyStruct {
int a;
int b;
float f;
SubStruct ss;
};
template <typename Tmember>
auto addTogether(Tmember member) {
MyStruct s1 = {.a = 1, .b =2, .f =3.3, .ss = {.c = 4}};
MyStruct s2 = {.a = 10, .b =20, .f =30.0, .ss = {.c = 40}};;
return s1.*(member) + s2.*(member);
}
int main() {
std::cout << "sum a = " << addTogether(&MyStruct::a) << std::endl;
std::cout << "sum b = " << addTogether(&MyStruct::b) << std::endl;
std::cout << "sum f = " << addTogether(&MyStruct::f) << std::endl;
//std::cout << "sum c = " << addTogether(&MyStruct::ss::c) << std::endl; //DOES NOT WORK
//std::cout << "sum c = " << addTogether(&MyStruct::ss.c) << std::endl; //DOES NOT WORK
return 0;
}
输出符合预期:
sum a = 11
sum b = 22
sum f = 33.3
但是如何将指针传递给数据成员ss.c?请参阅main()中两个注释掉的行。
感谢。