我在AWS Glue中使用python3.6在环境pyspark中工作。我有这张桌子:
+----+-----+-----+-----+
|year|month|total| loop|
+----+-----+-----+-----+
|2012| 1| 20|loop1|
|2012| 2| 30|loop1|
|2012| 1| 10|loop2|
|2012| 2| 5|loop2|
|2012| 1| 50|loop3|
|2012| 2| 60|loop3|
+----+-----+-----+-----+
我需要输出如下输出:
year month total_loop1 total_loop2 total_loop3
2012 1 20 10 50
2012 2 30 5 60
我越接近SQL代码:
select a.year,a.month, a.total,b.total from test a
left join test b
on a.loop <> b.loop
and a.year = b.year and a.month=b.month
到目前为止输出:
+----+-----+-----+-----+
|year|month|total|total|
+----+-----+-----+-----+
|2012| 1| 20| 10|
|2012| 1| 20| 50|
|2012| 1| 10| 20|
|2012| 1| 10| 50|
|2012| 1| 50| 20|
|2012| 1| 50| 10|
|2012| 2| 30| 5|
|2012| 2| 30| 60|
|2012| 2| 5| 30|
|2012| 2| 5| 60|
|2012| 2| 60| 30|
|2012| 2| 60| 5|
+----+-----+-----+-----+
我怎么能这样做?非常感谢
答案 0 :(得分:2)
表脚本和示例数据
CREATE TABLE [TableName](
[year] [nvarchar](50) NULL,
[month] [int] NULL,
[total] [int] NULL,
[loop] [nvarchar](50) NULL
)
INSERT [TableName] ([year], [month], [total], [loop]) VALUES (N'2012', 1, 20, N'loop1')
INSERT [TableName] ([year], [month], [total], [loop]) VALUES (N'2012', 2, 30, N'loop1')
INSERT [TableName] ([year], [month], [total], [loop]) VALUES (N'2012', 1, 10, N'loop2')
INSERT [TableName] ([year], [month], [total], [loop]) VALUES (N'2012', 2, 5, N'loop2')
INSERT [TableName] ([year], [month], [total], [loop]) VALUES (N'2012', 1, 50, N'loop3')
INSERT [TableName] ([year], [month], [total], [loop]) VALUES (N'2012', 2, 60, N'loop3')
使用Pivot功能...
SELECT *
FROM TableName
PIVOT(Max([total])
FOR [loop] IN ([loop1], [loop2], [loop3]) ) pvt
在线演示:http://www.sqlfiddle.com/#!18/164a4/1/0
如果您正在寻找动态解决方案,请尝试此操作...(动态数据透视)
DECLARE @cols AS NVARCHAR(max) = Stuff((SELECT DISTINCT ',' + Quotename([loop])
FROM TableName
FOR xml path(''), type).value('.', 'NVARCHAR(MAX)'), 1, 1, '');
DECLARE @query AS NVARCHAR(max) = 'SELECT *
FROM TableName
PIVOT(Max([total])
FOR [loop] IN ('+ @cols +') ) pvt';
EXECUTE(@query)
在线演示:http://www.sqlfiddle.com/#!18/164a4/3/0
输出
+------+-------+-------+-------+-------+
| year | month | loop1 | loop2 | loop3 |
+------+-------+-------+-------+-------+
| 2012 | 1 | 20 | 10 | 50 |
| 2012 | 2 | 30 | 5 | 60 |
+------+-------+-------+-------+-------+
答案 1 :(得分:1)
您不需要使用join
条件聚合:
select year, month,
max(case when loop = 'loop1' then total end) loop1,
max(case when loop = 'loop2' then total end) loop2,
max(case when loop = 'loop3' then total end) loop3
from test a
group by year, month;
答案 2 :(得分:1)
您可以使用PIVOT()
将行转换为列:
SELECT
year,
MONTH,
p.loop1 AS 'total_loop1',
p.loop2 AS 'total_loop2',
p.loop3 AS 'total_loop3'
FROM
tablename
PIVOT
(MAX(total)
FOR loop IN ([loop1], [loop2], [loop3])
) AS p;