Question

努力弄清楚如何处理从被动请求中收到的异常并将其冒泡（正文和Http状态代码将是最低限度的信息）。

我希望使用提到的here的ExchangeFilterFunction，但似乎无法捕获错误。我知道它已通过方法注册并运行

public class MyExchangeFilterFunction implements ExchangeFilterFunction {

    @Override
    public Mono<ClientResponse> filter(ClientRequest request, ExchangeFunction next) {
        return next.exchange(request).onErrorMap(MyError.class, c -> new RuntimeException("Ow"));
    }
}

注册过滤功能：

WebClient.builder().filter(new MyExchangeFilterFunction())...

转换成错误（因为我无法弄清楚如何冒泡）：

@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
public class MyError extends RuntimeException{
    private Long timestamp;
    private String path;
    private Integer status;
    private String error;
    private String message;
}

--------更新-------

错误现在被最新代码抛出，但无法弄清楚如何将响应体堵塞到Flux / Mono错误中。

@Override
public Mono<ClientResponse> filter(ClientRequest request, ExchangeFunction next) {
    return next.exchange(request).map(cr -> {
    if(cr.statusCode().isError()) {
        return ClientResponse.from(cr).body(
                Flux.error(new RuntimeException("OW"))
                ).build();
    } else {
        return cr;
    }

    });
}

Answer 1

让Exception Handling Reactive更进一步。

return ClientResponse.from(cr)
        .body(cr.body(BodyExtractors.toFlux(AnError.class))
        .flatMap(err -> Flux.error(new PassThroughException(err))))
        .build();

然后在WebExceptionHandler中：

AnError error;
if(ex instanceof PassThroughException) {
    error = ((PassThroughException) ex).getAnError();
} else {
    ...
}

exchange.getResponse().setStatusCode(HttpStatus.resolve(error.getStatus()));
exchange.getResponse().getHeaders().add(HttpHeaders.CONTENT_TYPE, MediaType.APPLICATION_JSON_UTF8_VALUE);

byte[] bite = null;
try {
    bite = objectMapper.writeValueAsBytes(error);
} catch (JsonProcessingException jpe) {
    log.error("Unable to write error to client: {}", ex, jpe);
}
return exchange.getResponse().writeWith(Flux.just(exchange.getResponse().bufferFactory().wrap(bite)));

传递Webflux Http错误

1 个答案: