Question

所以，我开始为游戏编写代码，这次我想为启动器和游戏使用单独的类。所以基本上它是一个单线程游戏，并且线程是在启动器中制作并启动的，而Game类是＆＃34; Runnable＆＃34;用run方法。问题是即使我启动线程，run方法也不会被调用。

启动器：

public class Launcher {

private Thread thread;

private static Game game;

public static void main(String[] args) {
    Launcher obj = new Launcher();
    game = new Game();

    obj.start();
}

public synchronized void start() {
    if(game.running) return;
    game.running = true;

    thread = new Thread(game);
    thread.start();
}

public synchronized void stop() {
    if(!game.running) return;
    game.running = false;

    try {
        thread.join();
    } catch (InterruptedException e) {
        e.printStackTrace();
    }
}

}

游戏课程：

public class Game extends JFrame implements Runnable{

public boolean running = false;
private static int WIDTH = 1280 , HEIGHT = 720;

private Screen screen;

public Game() {
    this.setTitle("Game");
    this.setSize(WIDTH, HEIGHT);
    this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    this.setLocationRelativeTo(null);

    this.running = true;

    this.setVisible(true);

    init();
}

public void init() {
    screen = new Screen(WIDTH, HEIGHT);
    this.add(screen);
    screen.init();

    this.pack();
}

public void render() {
    Screen.clearScreen();


    Screen.update();
}

public void update() {

}

@Override
public void run() {
    System.out.println("called"); //Checking if it was called, and it is not being called

    long lastTime = System.nanoTime();
    long now;
    int fps = 60;
    double timePerTick = 1000000000/fps;
    double delta = 0;

    while(running) {
        now = System.nanoTime();
        delta += (now - lastTime) / timePerTick;
        lastTime = now;

        if(delta >= 1){
            update();
            delta--;
        }

        render();
    }

}

}

Answer 1

创建new Game()时，设置running = true。稍后你会在你的发射器if(game.running) return中检查它是否为真，然后返回。

无关：支持封装不要像运行那样暴露公共字段。只是公开一些方法，告诉你这些信息，如：

  public class Game{
    private boolean running;
    ...
    public boolean isRunning(){ 
      return running; 
    }
  }

Answer 2

在此构造函数中

public Game() {
    this.setTitle("Game");
    this.setSize(WIDTH, HEIGHT);
    this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    this.setLocationRelativeTo(null);

    this.running = true;

    this.setVisible(true);

    init();
}

您必须设置this.running = false;才能启动游戏主题。

Answer 3

创建游戏时，将if expression1: statement(s) elif expression2: statement(s) else: statement(s)设置为true：

running

当你打电话给start时，你会检查它是否已经在运行，如果是，你会提前返回：

public Game() {
    //...
    this.running = true;

所以你总是在做任何事情之前退出这个方法。

我启动线程时没有调用Run。 Java的

3 个答案: