转移到向量的右侧元素

Question

用户输入保存在矢量中的N个数字序列。程序首先向向量元素的左侧移动，并将0分配给最后一个元素。然后它转移到新向量元素的右侧，并将0分配给第一个元素。

问题：我无法正确转移到正确的位置，导致输出错误，但我不明白我犯了什么错误。请参阅//SHIFT TO THE RIGHT//和vet[0]=0。

    #include <stdio.h>

int main(void)
{
    const int maxn=300; //max vector dimension
    int N; //vector dimension
    int vet[maxn]; 
    int i; //index

    do 
    {
        printf("how many numbers will be entered?");
        scanf("%d", &N);

        if (N>maxn || N<=0)
        {
            printf("ERROR.The number must be between 0 and %d\n", maxn);
        }
        printf("\n");
    }
    while (N>maxn || N<=0);

    printf("Enter a sequence of %d numbers\n", N);
    printf("\n");

    for (i=0; i<N; i++)
    {
        printf("element number %d: ", i+1);
        scanf("%d", &vet[i]);
    }
    printf("\n");

    printf("the sequence entered is:\n");
    for (i=0; i<N; i++)
    {
        printf("%d  ", vet[i]);
    }
    printf("\n");


    //SHIFT TO THE LEFT//
    //1 2 3 4 -> 2 3 4 0//

    for(i=0; i<N-1; i++)
    {
        vet[i]=vet[i+1];
    }
    vet[N-1]=0;


    printf("The resulting sequence from the shift to the left is:\n");
    printf("\n");

    for (i=0; i<N; i++)
    {
        printf("%d  ", vet[i]);
    }
    printf("\n");

    //SHIFT TO THE RIGHT//
    // 2 3 4 0 -> 0 2 3 4//
    for (i=N-1; i>0; i--);
    {
        vet[i]=vet[i-1];
    }
    vet[0]=0;


    printf("The resulting sequence from the shift to the right is: \n");
    printf("\n");

    for (i=0; i<N; i++)
    {
        printf("%d  ", vet[i]);
    }
    printf("\n");

    return(0);
}