Question

这是我的数据库架构

学生表：

var arr = [
  [
    "1947-01-01",
    243.1
  ],
  [
    "1947-04-01",
    246.3
  ],
  [
    "1947-07-01",
    250.1
  ]
];
var output = arr.map(s => ({
  date: s[0],
  gdp: s[1]
}));
console.log(output);

班级表：

studentid (PK)   |studentname 

1                |A

教学表：

classid (PK)     |classname    

1                |Math
2                |Science

测验表：

teachid  (PK)    |  classid   |   studentid 

1                |  1         |   1
2                |  2         |   1

quizscore table：

quizid  (PK)     |classid     | quizname

1                |1           | mathquiz
2                |2           | science quiz

这是我使用的SQL查询：

quizscoreid(PK)  | quizid     |studentid   |score
1                | 1          |1           |60
2                | 2          |1           |0

及其输出如下：

SELECT
    quiz.quizid,
    teach.classid,
    student.studentname,
    student.studentid,
    quizscore.score,
    quiz.quizname,
    class.classname
FROM teach 
INNER JOIN class
    ON teach.classid = class.classid
INNER JOIN student
    ON teach.studentid = student.studentid
INNER JOIN quiz
    ON quiz.classid = '1'
LEFT JOIN quizscore
    ON teach.studentid = quizscore.studentid
WHERE
    teach.classid='1' AND
    teach.classid = quiz.classid AND
    quiz.quizid = '1'
ORDER BY studentid ASC

虽然我期待这样：

studentid   |quizid    |classid    | studentname  |classname   | quizname   | score
1           |    1     |1          |  A           |Math        | mathquiz   | 60
1           |    1     |1          |  A           |Science     | mathquiz   | 0

请帮我纠正我的SQL查询

Answer 1

SELECT 
A.studentid, 
D.quizid, 
A.classid, 
C.studentname, 
B.classname, 
D.quizname, 
E.score
FROM
teach A 
LEFT JOIN class B ON A.classid=B.classid
LEFT JOIN student C ON A.studentid=C.studentid
LEFT JOIN quiz D ON A.classid=D.classid
LEFT JOIN quizscore E ON D.quizid=E.quizid AND E.studentid=A.studentid
WHERE 
A.studentid=1 AND 
D.quizid=1 AND  
A.classid=1;

DEMO

Mysql查询多个内连接和左连接

1 个答案: