Question

我需要在字符串中找到特定的模式并从中提取子字符串。字符串的例子：

{'Opening Cost P&L per store','Opening Costs Capital per store','Average Monthly Revenue','GROSS MARGIN %'}] = N:DB('Store Cost', 
    !Country and Region, DB('New Store Plan', !Country and Region, 
    !ID numbers, !Budget version, 'Retailer Type'), ATTRS('New Stores', 
    !New Stores, '}Map_}Link_New Store Plan_3CStore Cost'), DB('New Store Plan', 
    !Country and Region, !ID numbers, !Budget version, 'Size'), 
    DB('New Store Plan', !Country and Region, !ID numbers, !Budget version, 
    'Franchise/Corporate'), 'DATA')

我必须搜寻：
仅DB('，而不是S:DB('或DB('}等其他模式。

然后在找到这个模式之后，我必须在列表中选择文本，该文本在此模式之后和引号中可用例如

DB('Metrics cube-HumanResource',    !country, !Time, !gometric, !Metric Indicators), CONTINUE)
DB('Metrics cube-InternalProcess',     !country, 'Total of Product', !Time, !gometric, !Metric Indicators), CONTINUE);

然后输出将是：

1 - Metrics cube-HumanResource
2 - Metrics cube-InternalProcess

这是我的代码。但它不打印任何东西：

public class StringRegex {
    public static void main(String[] args) {
        String str = "{'Opening Cost P&L per store','Opening Costs Capital per store','Average Monthly Revenue','GROSS MARGIN %'}] = N:DB('Store Cost', \n" +
                "    !Country and Region, DB('New Store Plan', !Country and Region, \n" +
                "    !ID numbers, !Budget version, 'Retailer Type'), ATTRS('New Stores', \n" +
                "    !New Stores, '}Map_}Link_New Store Plan_3CStore Cost'), DB('New Store Plan', \n" +
                "    !Country and Region, !ID numbers, !Budget version, 'Size'), \n" +
                "    DB('New Store Plan', !Country and Region, !ID numbers, !Budget version, \n" +
                "    'Franchise/Corporate'), 'DATA')";
        String[] strArray = str.split(",");
        for(String s : strArray){
            if(s.matches("DB\\('.+'")){
                System.out.println(s);
            }
        }
    }
}

Answer 1

我会选择Pattern和Matcher，而不是分割String。您将获得更轻松的结果。使用以下正则表达式：

.*?[^:]DB\((.*?)\).*?

这将捕获不在:之前的每个数据库（。*）的内容。使用延迟量词*?将阻止捕获问题，而不仅仅是文本，直到结束括号。

来自Regex101：

    String regex = ".*?[^:]DB\\((.*?)\\).*?";
    String string = "{'Opening Cost P&L per store','Opening Costs Capital per store','Average Monthly Revenue','GROSS MARGIN %'}] = N:DB('Store Cost', \n"
            + "    !Country and Region, DB('New Store Plan', !Country and Region, \n"
            + "    !ID numbers, !Budget version, 'Retailer Type'), ATTRS('New Stores', \n"
            + "    !New Stores, '}Map_}Link_New Store Plan_3CStore Cost'), DB('New Store Plan', \n"
            + "    !Country and Region, !ID numbers, !Budget version, 'Size'), \n"
            + "    DB('New Store Plan', !Country and Region, !ID numbers, !Budget version, \n" + "    'Franchise/Corporate'), 'DATA')";

    Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE | Pattern.DOTALL);
    Matcher matcher = pattern.matcher(string);

    while (matcher.find()) {
        System.out.println("> " + matcher.group(1));
    }

结果：

> 'New Store Plan', !Country and Region, 
    !ID numbers, !Budget version, 'Retailer Type'  
> 'New Store Plan', 
    !Country and Region, !ID numbers, !Budget version, 'Size'  
> 'New Store Plan', !Country and Region, !ID numbers, !Budget version, 
    'Franchise/Corporate'

正则表达式在java

1 个答案: