Question

我使用Python3 Beautiful Soup废弃网站。这是我得到的XML数据。

<?xml version="1.0" encoding="utf-8"?>
        <title type="text">MATERIALSET('R100100100')</title>
        <updated>2018-05-11T04:28:47Z</updated>
        <category term="ZPOC_BOT_PUR_GRP_SRV.MATERIAL" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme"/>
        <link href="MATERIALSET('R100100100')" rel="self" title="MATERIAL"/>
        <content type="application/xml">
            <m:properties>
                <d:MATNR>R100100100</d:MATNR>
                <d:WERKS>Z100</d:WERKS>
                <d:MENGE>       1.000</d:MENGE>
                <d:EEIND>29.06.2018</d:EEIND>
                <d:BANFN>5000000041</d:BANFN>
            </m:properties>
        </content>
    </entry>

我只想在d：BANFN中提取数据。如果我直接写出soup.select（＆＃39; d：BANFN＆＃34;），则显示错误为'nth_child_of_type＆＃39;。我确实在Stackoverflow中经历了一些问题，这里是链接 - Getting the nth element using BeautifulSoup 和 selecting second child in beautiful soup with soup.select? 但没有任何帮助。请帮忙。

Answer 1

在xml文件中应该有entry属性的起始标记，然后只能解析xml文件：

<!-- Sample.xml contains following data: -->
<?xml version="1.0" encoding="utf-8"?>
    <entry>
        <title type="text">MATERIALSET('R100100100')</title>
        <updated>2018-05-11T04:28:47Z</updated>
        <category term="ZPOC_BOT_PUR_GRP_SRV.MATERIAL" scheme="http://schemas.microsoft.com/ado/2007/08/dataservices/scheme"/>
        <link href="MATERIALSET('R100100100')" rel="self" title="MATERIAL"/>
        <content type="application/xml">
            <m:properties>
                <d:MATNR>R100100100</d:MATNR>
                <d:WERKS>Z100</d:WERKS>
                <d:MENGE>       1.000</d:MENGE>
                <d:EEIND>29.06.2018</d:EEIND>
                <d:BANFN>5000000041</d:BANFN>
            </m:properties>
        </content>
    </entry>

from bs4 import BeautifulSoup
with open("sample.xml", "r") as f: # opening xml file
    content = f.read() # xml content stored in this variable and decode to utf-8

soup = BeautifulSoup(content, 'lxml') #parse content to BeautifulSoup Module

print("BANFN value : {}".format([ item.text for item in soup.find_all("d:banfn")][0])) #required result

#output:
BANFN value : 5000000041

使用BeautifulSoup Python3获取第n个孩子

1 个答案: