C ++:Segmentation Fault,malloc.c:没有这样的文件或目录

时间:2018-05-11 02:52:53

标签: c++ segmentation-fault malloc sigsegv

我在C ++中解决了编程problem,需要检查所有9个! 3 X 3矩阵的置换

1 2 3

4 5 6

7 8 9

我认为,我已经编写了正确的逻辑,并且在2 X 2矩阵上进行了测试(通过从3 X 3中调整2 X 2的代码,当然。),这导致正确的输出被打印。但是当我为实际约束运行程序(即3 X 3 matirx)时,程序终止于Segmentation故障。奇怪的是,当与GDB进行混淆时,它打印出来

Program received signal SIGSEGV, Segmentation fault.
0x00007ffff74f6bbc in _int_malloc (av=av@entry=0x7ffff7839b20 <main_arena>, 
    bytes=bytes@entry=12) at malloc.c:3353
3353    malloc.c: No such file or directory.

这是我写的C ++代码:

#include <bits/stdc++.h>
using namespace std;

int min_count;
map<string, bool> mp;
vector<vector<int>>vec(3, vector<int>(3, 0));

// n <= 17
bool isPrime(int n) {
    return n == 2 or n == 3 or n == 5 or n == 7 or n == 11 or n == 13 or n == 17;
}

// get a String representation of the matrix vec
string getStringRepresentation(vector<vector<int>> vec) {
    string str = "";
    for(auto i : vec) {
        for(auto j : i)
            str += ('0' + j);
    }
    return str;
}

void printRecursive(vector<vector<int>> &vec, map<string, bool> &mp, int count) {
    string str = getStringRepresentation(vec);
    if(str == "123456789" and count <= min_count)
        min_count = count;
    //cout << str << " " << count << endl;
    if(mp[str])
        return;
    mp[str] = true;

    for(int i = 0; i < vec.size(); ++i) {
        for(int j = 0; j < vec[i].size(); ++j) {
            if(j != vec[i].size() - 1 and isPrime(vec[i][j] + vec[i][j+1])) {
                swap(vec[i][j], vec[i][j+1]);
                printRecursive(vec, mp, count + 1);
                swap(vec[i][j], vec[i][j+1]);
            }

            if(i != vec.size() - 1 and isPrime(vec[i][j] + vec[i+1][j])) {
                swap(vec[i][j], vec[i+1][j]);
                printRecursive(vec, mp, count + 1);
                swap(vec[i][j], vec[i+1][j]);
            }

        }
    }
}

// solve for each test case
void solve() {

    for(auto &i : vec)  {
        for(auto &j : i) {
            cin >> j;
        }
    }

    //cout << getStringRepresentation(vec) << endl;


    min_count = INT_MAX; 

    printRecursive(vec, mp, 0); // recursively examine all possible states.
    // if min_count is not changed(i.e. reamains equal to INT_MAX then the required state is unreachable, print -1 to indicate)
    cout << (min_count == INT_MAX ? -1 : min_count) << endl; 
}

int main() {
    int test; // test are the number of test cases, each will invoke the solve() function.
    cin >> test;

    while(test--)
        solve();
}

输入

1

7 3 2 
4 1 5 
6 8 9

该计划应该输出6,但会产生SIGSEGV,如上所述。我做错了什么?

0 个答案:

没有答案