Question

我正在用c ++ / clr编写一个程序，我需要编写词法分析器。我有这些：

std::map <std::string, int> classes = { { "keyword",0 },{ "identifier",0 },{ "digit",0 },{ "integer",0 },{ "real",0 },{ "character",0 },{ "alpha",0 } };
std::vector<std::string> ints = { "0","1","2","3","4","5","6","7","8","9" };
std::vector<std::string> keywords = { "if","else","then","begin","end" };
std::vector<std::string> identifiers = { "(",")","[","]","+","=",",","-",";" };
std::vector<std::string> alpha = { "a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z" };
std::vector<std::string>::iterator iter;

所以这就是问题所在：它将classes，ints，keywords e.t.c标记为错误： a member of managed class cannot be of a non-managed class type

我该如何解决这个问题？

Answer 1

我看到你正在使用C ++ / clr，所以我认为你有充分的理由。

本机类型不能是Managed类的成员。原因是机器必须知道何时销毁/解除本机代码占用的内存 - ＆gt;它们位于管理类中，对象被垃圾收集器破坏。

无论如何，您可以将托管类型用作类成员...或指向本机类型的指针作为类成员 - 除非您想要从Manage转换为Native或反之亦然，否则不建议使用。这是一个例子：

// compile with: /clr
#include "stdafx.h"
#include <vector>
#include <iostream>
#include <string>

using namespace System;
using namespace System::Collections::Generic;

public ref class MyClass
{
private:
    //std::vector<std::string> ints; // Native C++ types can not be members of Managed class
    List<String^>^ ints; // Managed types can be class members
    std::vector<std::string>* native_ints; // However You can have pointer to native type as class member

public:
    MyClass()
    { // Initialize lists with some values
        ints = gcnew List<String^>(gcnew array<System::String^>{ "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" }); // Managed initialization
        native_ints = new std::vector<std::string>{ "a", "b", "c" }; // Native initialization
    }

    ~MyClass()
    {
        delete native_ints; // Native (not Managed) memory allocation have to be deleted
    }

    void Print()
    {
        Console::WriteLine("Managed List: {0}", String::Join(", ", ints->ToArray()));
        std::cout << "Native vector: " << (*native_ints)[0] << ", " << (*native_ints)[1] << ", " << (*native_ints)[2];
    }
};


int main(array<System::String ^> ^args)
{
    MyClass^ mc = gcnew MyClass();
    mc->Print();

    return 0;
}

控制台输出是：

Managed List: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
Native vector: a, b, c

类型等价物：

std::vector - ＆gt; List<T>
std::map - ＆gt; SortedDictionary<Tkey, Tvalue>
std::string - ＆gt; String

不要忘记托管类型的^

托管类的成员不能是非托管类类型

1 个答案: