我正在尝试使用Curl和PHP发布文件。
我按照说明操作:
提交文件
使用带有encType:multipart / form-data的HTTPs POST提交上传文件(用于存款或批量查询)。所有提交的URL都是https:// doi.crossref.org/servlet/deposit。您也可以使用https://test.crossref.org/servlet/deposit将提交内容发布到我们的测试系统。
使用curl的例子:
上传文件:
curl -F'operation = doQueryUpload'-F'login_id = USERNAME'-F'login_passwd = PASSWORD'-F'fname = @ FILENAME'https:// doi.crossref.org/servlet/deposit
这是我正在尝试的代码
<?php
ini_set('display_errors', E_ALL);
define('CROSSREF_API_URL', 'https://test.crossref.org/servlet/deposit');
define('CROSSREF_API_DEPOSIT_OK', 303);
define('CROSSREF_API_RESPONSE_OK', 200);
echo registerDoi(realpath('test.xml'));
function registerDoi($filename) {
$curlCh = curl_init();
curl_setopt($curlCh, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curlCh, CURLOPT_POST, true);
curl_setopt($curlCh, CURLOPT_HEADER, 1);
curl_setopt($curlCh, CURLOPT_BINARYTRANSFER, true);
$username = 'username';
$password = '123456';
curl_setopt($curlCh, CURLOPT_URL, CROSSREF_API_URL);
curl_setopt($curlCh, CURLOPT_USERPWD, "$username:$password");
// Transmit XML data.
assert(is_readable($filename));
$fh = fopen($filename, 'rb');
$httpheaders = array();
$httpheaders[] = 'Content-Type: application/vnd.crossref.deposit+xml';
$httpheaders[] = 'Content-Length: ' . filesize($filename);
curl_setopt($curlCh, CURLOPT_HTTPHEADER, $httpheaders);
curl_setopt($curlCh, CURLOPT_INFILE, $fh);
curl_setopt($curlCh, CURLOPT_INFILESIZE, filesize($filename));
$response = curl_exec($curlCh);
if ($response === false) {
$result = 'response from server.';
} elseif ( $status = curl_getinfo($curlCh, CURLINFO_HTTP_CODE) != CROSSREF_API_DEPOSIT_OK ) {
$result = $response;
} else {
// Deposit was received
$result = 'recebido';
}
curl_close($curlCh);
return $result;
}
&GT;
这是错误:
HTTP / 1.1 405方法不允许服务器:Apache-Coyote / 1.1 Crossref-Deployment-Name:cs3-1 Content-Type:text / plain; charset = UTF-8 Content-Language:en-US Content-Length: 17日期:2018年5月10日星期四17:18:10 GMT连接:关闭Strict-Transport-Security:max-age = 15768000 GET不支持
任何想法我怎么能把这个文件?
修改
我按照@waterloomatt的说明进行操作,现在又出现了另一个错误
这是代码:
<!DOCTYPE html>
<html>
<body>
<form action="deposito.php" method="post" name="frmUpload" enctype="multipart/form-data">
<tr>
<td>Upload</td>
<td align="center">:</td>
<td><input name="file" type="file" id="file"/></td>
</tr>
<tr>
<td> </td>
<td align="center"> </td>
<td><input name="btnUpload" type="submit" value="Upload" /></td>
</tr>
</body>
</html>
<?php
if (isset($_POST['btnUpload']))
{
$url = "https://test.crossref.org/servlet/deposit";
$filename = $_FILES['file']['name'];
$filedata = $_FILES['file']['tmp_name'];
$filesize = $_FILES['file']['size'];
$username = 'usename';
$password = '1234';
if ($filedata != '')
{
$headers = array("Content-Type:multipart/form-data"); // cURL headers for file uploading
$postfields = array("filedata" => "@$filedata", "fname" => $filename);
$ch = curl_init();
$options = array(
CURLOPT_URL => $url,
CURLOPT_HEADER => true,
CURLOPT_POST => 1,
CURLOPT_HTTPHEADER => $headers,
CURLOPT_POSTFIELDS => $postfields,
CURLOPT_INFILESIZE => $filesize,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_USERPWD => "$username:$password",
CURLOPT_BINARYTRANSFER => true
); // cURL options
curl_setopt_array($ch, $options);
$errmsg = curl_exec($ch);
curl_close($ch);
}
else
{
$errmsg = "Please select the file";
}
echo $errmsg;
}
错误消息:
HTTP / 1.1 100继续HTTP / 1.1 401未经授权的服务器:Apache-Coyote / 1.1 Crossref-Deployment-Name:cs3-1 Set-Cookie:JSESSIONID = B2110CC01E3542D50E21D9898D4FD5F2; Path = / Content-Type:text / plain; charset = UTF-8 Content-Language:en-US Content-Length:24 Date:Monday,November May 14:13:07 GMT Connection:close Strict-Transport-Security: max-age = 15768000请求中没有登录信息
有谁知道为什么登录名和密码无法被识别?
答案 0 :(得分:0)
我有同样的问题。我做了什么:
首先,将URL作为参数添加到 curl_init
$ch = curl_init($url);
第二,使用类CURLFile代替 @ 。
最后,像这样发送凭据,而不是CURLOPT_USERPWD。 p>
$postfields = array(
'login_id' => $username,
'login_passwd' => $password,
'fname' => new CURLFile($filedata),
);
答案 1 :(得分:-1)
如果有帮助,请使用本文。 Upload files with CURL