我正在尝试使用tempToFahrenheit: function(tempInC){
tempInF = (tempInC*1.8)+32;
return tempInF;
},
getTextWeatherUsingStationUsingRequest: function(theStation){
const http = require("http");
const https = require("https");
// theURL = 'https://api.weather.gov/stations/' + theStation + '/observations/current';
thePath = '/stations/' + theStation + '/observations/current';
function requestTheData(){
var returnedJSON;
var options = {
protocol: "https:",
hostname: "api.weather.gov",
path: thePath,
method: "GET",
headers: {
'Accept' : 'application/json',
'Content-Type': 'application/json',
'User-Agent' : 'MY-TEST-UA'
}
};
var req= https.request(options);
var theData = '';
req.on("response", function(res){
console.log(`STATUS: ${res.statusCode}`);
console.log(`HEADERS: ${JSON.stringify(res.headers)}`);
res.on('data', (chunk) => {
console.log(`BODY: ${chunk}`);
theData += chunk;
});
res.on('end', () => {
console.log('No more data in response.');
returnedJSON = JSON.parse(theData);
console.log(returnedJSON.id);
// Why can't ot find temptoFahrenheit
theTemp = Math.round( tempToFahrenheit(returnedJSON.properties.temperature.value) )
windSpeed = Math.round(returnedJSON.properties.windSpeed.value);
pressure = returnedJSON.properties.barometricPressure.value;
函数创建一个带有URL的对象，创建get请求，然后返回GET。但是，使用我当前的代码，每当我尝试记录它时，我都会得到responseText。
undefined编辑：在这个问题被标记为重复后，我会查看我'重复'的问题并解决了我的问题，但我不明白为什么var HttpRequest = function() {
this.get = function(url, callback) {
var httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = function() {
if(httpRequest.readyState == 4 && httpRequest.status == 200) {
callback = httpRequest.responseText;
}
};
httpRequest.open("GET", url, true);
httpRequest.send(null);
return callback;
};
};
var request = new HttpRequest();
var response = request.get("https://min-api.cryptocompare.com/data/price?fsym=BTC&tsyms=BTC,USD");
console.log(response);
无效。我已经将我的代码更新为应该工作的东西，但是没有。回调函数是在某些事情完成后调用的函数，但为什么return不能代替它？
更新的代码： var HttpRequest = function（）{ this.get = function（url）{
return