Question

我正在使用PHP和MySQL数据库来完成我的学校项目。当我尝试在数据库中导入数据时遇到问题。在第一个表（murid表）中它完美地工作，但在第二个表（pendaftaran表）中，它似乎导入了两次。这是我的PHP代码。我想知道为什么我的数据在pendaftaran表中插入两次？

<?php
session_start();
$username = $_SESSION['username'];
$conn = mysqli_connect('localhost','root','','darksith');

if(!$conn)
{
    echo 'Not connected';   
}


if (isset($_POST['importbutton'])) {
    $namaFail = $_FILES['file']['tmp_name'];

    if ($_FILES['file']['size'] > 0) {
      $fail = fopen($namaFail, 'r');

      while (!feof($fail)) {
        $data = fgetcsv($fail, '0');

        $query = "SELECT * FROM murid WHERE No_Sekolah_Murid = '".$data[0]."'";
        $result = mysqli_query($conn, $query);

        if (empty($data[0] || $data[1] || $data[2] || $data[3])) {
          echo "<script>
              window.alert('Sila isikan semua medan dalam fail!');
              window.location = '';
              </script>";
          //exit();
        } else {

          if (mysqli_num_rows($result) === 0) {
            $query1 = "INSERT INTO murid(No_Sekolah_Murid, Nama_Murid, Kelas, Tarikh_Daftar) VALUES('".$data[0]."', '".$data[1]."', '".$data[2]."',NOW())";

            $query2 = "INSERT INTO pendaftaran(ID_Pendaftaran, ID_Pengguna, No_Sekolah_Murid, Kod_Pertubuhan) VALUES('', '$username', '".$data[0]."', '".$data[3]."')";

            mysqli_query($conn, $query1);
            var_dump(mysqli_query($conn, $query1));
            mysqli_query($conn, $query2);
            var_dump(mysqli_query($conn, $query2));


          // echo "<script>
              // window.alert('Rekod berjaya ditambahkan!');
              // window.location = 'import.html';
              // </script>";
          } else {
            "<script>
          window.alert('Rekod gagal ditambahkan!');
          window.location = 'import.html';
          </script>";
          }
        }

      } fclose($fail);
    } 

} else {   
    echo "<script>
      window.alert('Import gagal. Sila cuba sekali lagi!');
      window.location = 'import.html';
      </script>";
    exit();
}

?>

Answer 1

更改下面提到的代码：

mysqli_query($conn, $query2);
var_dump(mysqli_query($conn, $query2));

到

$sqlExecRes = mysqli_query($conn, $query2);
var_dump($sqlExecRes);

为什么我的数据在MySQL中插入两次

1 个答案: