Question

我有以下脚本：

<?php
$main_image  = get_field('main_image');
$hover_image  = get_field('hover_image');
$button_text  = get_field('button_text');
?>


<img src="<?php echo $main_image; ?>"
onmouseover="this.src='<?php echo $hover_image; ?>'" 
onmouseout="this.src='<?php echo $main_image; ?>'" />

如何在鼠标悬停时显示<?php echo $button_text; ?>？

谢谢！

Answer 1

每当鼠标悬停事件运行时，您都可以使用img标签的title属性来显示$ button_text值。例如

<img src="<?php echo $main_image; ?>" title=""
onmouseover="this.src='<?php echo $hover_image; ?>'" 
onmouseout="this.src='<?php echo $main_image; ?>'" />

如果您想以不同的方式显示按钮文字，那么还让我知道您想要如何显示？所以我也可以帮助你。

Answer 2

Sub deleteDuplicate()

    Dim ws As Worksheet
    Dim wkbk1 As Workbook
    Dim w As Long
    Dim lRow As Long
    Dim iCntr As Long

    Set wkbk1 = Workbooks("3rd Party.xlsm")

    wkbk1.Activate

    For Each ws In ThisWorkbook.Worksheets

        ' Find last row in column A
        lRow = ws.Range("A" & ws.Rows.count).End(xlUp).Row

        For iCntr = lRow To 1 Step -1

            ws.lRow.RemoveDuplicates Columns:=1, Header:=xlYes

        Next iCntr

    Next ws

End Sub

我提供了一个与您的要求相关的示例，请查看此示例，如果您有任何疑虑，请告诉我。

添加第二个onmouseover操作

2 个答案: