如何知道Node x是否包含节点z的每个实例，它与另一个与另一个节点z有一个关系的节点y有很多关系？

Question

所以我有一个节点:Customer，其中包含许多节点:Order，而:Order与:Shipper节点:SHIP_VIA的关系必须为1 {}} ：

(customer:Customer)-[:PURCHASED]->(order)-[:SHIP_VIA]->(shipper:Shipper)

现在只有3个托运人，订单指向他们，而客户会有很多订单。所以我的问题是如何让所有托运人都附带所有客户？请注意，每个托运人都有一个shipperID属性。这是我的代码，但它没有工作，除了一个＆＃34; where exists＆＃34;

match (customer:Customer)-[:PURCHASED]->(order)-[:SHIP_VIA]->(shipper:Shipper) 

WHERE exists((customer)-[:PURCHASED]->(order)-[:SHIP_VIA]->(:Shipper 

{shipperID:1})) and exists((customer)-[:PURCHASED]->(order)-[:SHIP_VIA]->

(:Shipper {shipperID:2})) and exists((customer)-[:PURCHASED]->(order)-

[:SHIP_VIA]->(:Shipper {shipperID:3})) return  customer, order , shipper;

Answer 1

使用collect()和all()函数尝试此解决方案：

freq='20d'

Answer 2

1. 计算托运人总数
2. 对于每位客户，请确认唯一托运人的数量等于托运人总数

MATCH (shipper:Shipper) 
WITH count(shipper) AS totalShippers

MATCH (customer:Customer)-[:PURCHASED]->(order)-[:SHIP_VIA]->(shipper:Shipper)
WITH totalShippers, customer, 
     COUNT(DISTINCT shipper) as shippers WHERE totalShippers = shippers

RETURN customer