Question

我正在编写一个C ++程序，可以在阿拉伯语和罗马语编号系统之间进行转换。我写了一个程序，将阿拉伯语转换为罗马语，并有另一个程序将罗马语转换为阿拉伯语问题是我无法弄清楚如何将它们合并到一个程序中，以便用户可以输入阿拉伯语或罗马数字，因此程序会将所述数字转换为另一个。

我的问题是如何将这两个程序合并为一个？

罗马语到阿拉伯语的代码

#include <iostream>
using namespace std;
int main()
{
    char roman_Numeral;
    int arabic_Numeral = 0;

    cout << "Enter the Roman Numeral in Capital letters (e.g. CCXIX) : ";
    while (cin.get(roman_Numeral))
    {

        if (arabic_Numeral > 100)
        {
            cout << "\nInvalid Value. Number must be  between I and C" << endl;
            return 0;
        }

        else if (roman_Numeral == 'C')
        {
            roman_Numeral = cin.peek();
            if (roman_Numeral == 'M' || roman_Numeral == 'D')
            {
                arabic_Numeral = arabic_Numeral - 100;
            }
            else
            {
                arabic_Numeral = arabic_Numeral + 100;
            }

        }

        else if (roman_Numeral == 'L')
        {
            roman_Numeral = cin.peek();
            if (roman_Numeral == 'M' || roman_Numeral == 'D'
                    || roman_Numeral == 'C')
            {
                arabic_Numeral = arabic_Numeral - 50;
                continue;
            }
            else
            {
                arabic_Numeral = arabic_Numeral + 50;
                continue;
            }
        }

        else if (roman_Numeral == 'X')
        {
            roman_Numeral = cin.peek();
            if (roman_Numeral == 'M' || roman_Numeral == 'D'
                    || roman_Numeral == 'C' || roman_Numeral == 'L')
            {
                arabic_Numeral = arabic_Numeral - 10;
                continue;
            }
            else
            {
                arabic_Numeral = arabic_Numeral + 10;
                continue;
            }
        }

        else if (roman_Numeral == 'V')
        {
            roman_Numeral = cin.peek();
            if (roman_Numeral == 'M' || roman_Numeral == 'D'
                    || roman_Numeral == 'C' || roman_Numeral == 'L'
                    || roman_Numeral == 'X')
            {
                arabic_Numeral = arabic_Numeral - 5;
                continue;
            }
            else
            {
                arabic_Numeral = arabic_Numeral + 5;
                continue;
            }
        }

        else if (roman_Numeral == 'I')
        {
            roman_Numeral = cin.peek();
            if (roman_Numeral == 'M' || roman_Numeral == 'D'
                    || roman_Numeral == 'C' || roman_Numeral == 'L'
                    || roman_Numeral == 'X' || roman_Numeral == 'V')
            {
                arabic_Numeral = arabic_Numeral - 1;
                continue;
            }
            else
            {
                arabic_Numeral = arabic_Numeral + 1;
                continue;
            }
        }

        else
            break;
    }
    cout << arabic_Numeral << endl;
    return 0;
}

阿拉伯语到罗马的代码

#include <iostream>
#include <string>

#include <iomanip>
using namespace std;

#define MAX_INPUT 100 // These constants hold high and low integer numbers,
#define MIN_INPUT 1
#define ARRAY_SIZE 4   // and the array size declarator.

string convert(int digit, string low, string mid, string high);

int main()
{
    string answers[ARRAY_SIZE] = { "", "", "", "" }; //An  array of string to hold the output from the convert function.
    int accumulator = 0; // Variable to hold number of arabic numbers converted.
    int userNum = 0;
    string strUserNum;

    do
    {
        cout << "";
        cout << "Enter an arabic number between 1 and 100: ";
        cin >> strUserNum;

        userNum = std::stoi(strUserNum);

        if (userNum == 0 || userNum > MAX_INPUT)
        {
            cout << "\nInvalid Value. Number must be between 1 and 100" << endl;
            return 0;
        }
        else if (userNum == 'end')
        {
            cout << "Exiting program:";
            break;
        }

        int thous = userNum / 1000;

        int hund = userNum % 1000 / 100;

        int tens = userNum % 100 / 10;

        int ones = userNum % 10 / 1;

        answers[0] = convert(thous, "M", "M", "M");
        answers[1] = convert(hund, "C", "D", "M");

        answers[2] = convert(tens, "X", "L", "C");
        answers[3] = convert(ones, "I", "V", "X");

        cout << answers[0] << answers[1] << answers[2];
        cout << answers[3] << endl;
        cout << endl;
        break;

    } while (userNum != 'end');

    system("PAUSE");
    return 0;

}
string convert(int digit, string low, string mid, string high)
{

    if (digit == 1)
    {
        return low;
    }
    if (digit == 2)
    {
        return low + low;
    }
    if (digit == 3)
    {
        return low + low + low;
    }
    if (digit == 4)
    {
        return low + mid;
    }
    if (digit == 5)
    {
        return mid;
    }
    if (digit == 6)
    {
        return mid + low;
    }
    if (digit == 7)
    {
        return mid + low + low;
    }
    if (digit == 8)
    {
        return mid + low + low + low;
    }
    if (digit == 9)
    {
        return low + high;
    }
    if (digit == 0)
    {
        return "";
    }
}

Answer 1

将罗马字到阿拉伯语的代码（在主块内）放入void procedureRomanToArabic() 罗马到阿拉伯语也一样。将其放入void procedureArabicToRoman()。删除并删除ArabicToRoman执行时，并将其移至main。

void procedureRomanToArabic(){
    char roman_Numeral;
    int arabic_Numeral = 0;

    //...

    cout << arabic_Numeral << endl;
}




void procedureArabicToRoman()
{
    string answers[ARRAY_SIZE] = { "", "", "", "" }; //An  array of string to hold the output from the convert function.
    int accumulator = 0; // Variable to hold number of arabic numbers converted.
    int userNum = 0;
    string strUserNum;

    //remove do while here
    cout << "";
    cout << "Enter an arabic number between 1 and 100: ";
    cin >> strUserNum;

    //...

    answers[2] = convert(tens, "X", "L", "C");
    answers[3] = convert(ones, "I", "V", "X");

    cout << answers[0] << answers[1] << answers[2];
    cout << answers[3] << endl;
    cout << endl;
}


int main(){
  char type;
  do{

    cout<<"2 for Arabic to Roman, 1 for Roman to Arabic, or anything else for exit";
    cin>>type;
    if(type=='1')
        procedureArabicToRoman();
    else if(type =='2')
        procedureRomanToArabic();
    else break; //end program
  } while(true);     

}

C ++阿拉伯语数字给Roman Numeral＆amp; s;反之亦然

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