Question

我有一个xml如下。

<list>
    <map>
    <map name="CLAIM_TICKET_1">
    <val name="CLAIM_TICKET_Groups">Kalyan</val>
    <val name="Testing">Ram</val>
    </map>
    <map name="CLAIM_TICKET_2">
    <val name="CLAIM_TICKET_Groups">Raju</val>
    <val name="Testing">Varma</val>
    </map>
    </list>

我尝试使用digester将其作为Map对象检索。

我希望输出为：

作为地图对象的列表。

{CLAIM_TICKET_1={CLAIM_TICKET_Groups=Kalyan,Testing=Ram},
CLAIM_TICKET_2={CLAIM_TICKET_Groups=Raju,Testing=Varma}}

我的代码显示错误：

String Xpath =＆＃34; map / map＆＃34 ;;

digester.addObjectCreate(Xpath, HashMap.class);
    digester.addCallMethod(Xpath , "put", 2);
    digester.addCallParam(Xpath, 0, "name");        

    digester.addObjectCreate(Xpath, HashMap.class);
    digester.addCallMethod(Xpath+"/val" , "put", 2);
    digester.addCallParam(Xpath+"/val", 0, "name");        
    digester.addCallParam(Xpath+"/val", 1);

    digester.addSetNext(Xpath+"/val", "put");

Answer 1

    String Xpath = "map/map";
//For every occurence of list/map add map object to list object
    digester.addObjectCreate("list/map", ArrayList.class);

    digester.addObjectCreate(Xpath, HashMap.class);
    digester.addCallMethod(Xpath+"/val" , "put", 2);
    digester.addCallParam(Xpath+"/val", 0, "name");        
    digester.addCallParam(Xpath+"/val", 1);

digester.addSetNext("list/map", "add"); 


It works fine.

我想使用常见的消化器检索Map对象

1 个答案: