我试图创建一个动态的linq扩展方法,它以JSON格式返回一个字符串 - 我正在使用System.Linq.Dynamic和Newtonsoft.Json而我无法让Linq.Dynamic解析“ cell = new object []“part。也许太复杂了?有任何想法吗? :
我的主要方法:
static void Main(string[] args)
{
NorthwindDataContext db = new NorthwindDataContext();
var query = db.Customers;
string json = JSonify<Customer>
.GetJsonTable(
query,
2,
10,
"CustomerID"
,
new string[]
{
"CustomerID",
"CompanyName",
"City",
"Country",
"Orders.Count"
});
Console.WriteLine(json);
}
JSonify class
public static class JSonify<T>
{
public static string GetJsonTable(
this IQueryable<T> query,
int pageNumber,
int pageSize,
string IDColumnName,
string[] columnNames)
{
string selectItems =
String.Format(@"
new
{
{{0}} as ID,
cell = new object[]{{{1}}}
}",
IDColumnName,
String.Join(",", columnNames));
var items = new
{
page = pageNumber,
total = query.Count(),
rows =
query
.Select(selectItems)
.Skip(pageNumber * pageSize)
.Take(pageSize)
};
return JavaScriptConvert.SerializeObject(items);
// Should produce this result:
// {
// "page":2,
// "total":91,
// "rows":
// [
// {"ID":"FAMIA","cell":["FAMIA","Familia Arquibaldo","Sao Paulo","Brazil",7]},
// {"ID":"FISSA","cell":["FISSA","FISSA Fabrica Inter. Salchichas S.A.","Madrid","Spain",0]},
// {"ID":"FOLIG","cell":["FOLIG","Folies gourmandes","Lille","France",5]},
// {"ID":"FOLKO","cell":["FOLKO","Folk och fä HB","Bräcke","Sweden",19]},
// {"ID":"FRANK","cell":["FRANK","Frankenversand","München","Germany",15]},
// {"ID":"FRANR","cell":["FRANR","France restauration","Nantes","France",3]},
// {"ID":"FRANS","cell":["FRANS","Franchi S.p.A.","Torino","Italy",6]},
// {"ID":"FURIB","cell":["FURIB","Furia Bacalhau e Frutos do Mar","Lisboa","Portugal",8]},
// {"ID":"GALED","cell":["GALED","Galería del gastrónomo","Barcelona","Spain",5]},
// {"ID":"GODOS","cell":["GODOS","Godos Cocina Típica","Sevilla","Spain",10]}
// ]
// }
}
}
答案 0 :(得分:1)
这真的很难看,字符串替换可能存在一些问题,但它会产生预期的结果:
public static class JSonify
{
public static string GetJsonTable<T>(
this IQueryable<T> query, int pageNumber, int pageSize, string IDColumnName, string[] columnNames)
{
string select = string.Format("new ({0} as ID, \"CELLSTART\" as CELLSTART, {1}, \"CELLEND\" as CELLEND)", IDColumnName, string.Join(",", columnNames));
var items = new
{
page = pageNumber,
total = query.Count(),
rows = query.Select(select).Skip((pageNumber - 1) * pageSize).Take(pageSize)
};
string json = JavaScriptConvert.SerializeObject(items);
json = json.Replace("\"CELLSTART\":\"CELLSTART\",", "\"cell\":[");
json = json.Replace(",\"CELLEND\":\"CELLEND\"", "]");
foreach (string column in columnNames)
{
json = json.Replace("\"" + column + "\":", "");
}
return json;
}
}
答案 1 :(得分:0)
static void Main(string[] args)
{
NorthwindDataContext db = new NorthwindDataContext();
var query = db.Customers;
string json = query.GetJsonTable<Customer>(2, 10, "CustomerID", new string[] {"CustomerID", "CompanyName", "City", "Country", "Orders.Count" });
}
public static class JSonify
{
public static string GetJsonTable<T>(
this IQueryable<T> query, int pageNumber, int pageSize, string IDColumnName, string[] columnNames)
{
string select = string.Format("new ({0} as ID, new ({1}) as cell)", IDColumnName, string.Join(",", columnNames));
var items = new
{
page = pageNumber,
total = query.Count(),
rows = query.Select(select).Skip((pageNumber - 1) * pageSize).Take(pageSize)
};
return JavaScriptConvert.SerializeObject(items);
}
}
答案 2 :(得分:0)
感谢您的快速回复。 但是,请注意所需的输出在“单元格”数组中没有属性名称(这就是我使用object []的原因):
“cell”:[“FAMIA”,“Familia Arquibaldo”,... 与 “cell”:{“CustomerID”:“FAMIA”,“CompanyName”,“Familia Arquibaldo”,......
结果意味着与名为“flexify”的JQuery网格一起使用,该网格需要以此格式输出。