如何使用Entity Framework Core设置复杂对象?

时间:2018-05-09 10:00:32

标签: c# linq data-structures asp.net-core entity-framework-core

我有类似下面的类结构。我有一个主要类别,它可以有多个子类别,这些子类别可以进一步有子类别。我想从表中获取所有数据并将其设置为对象,然后将其转换为JSON。类别和子类别关系由ParentId维护。 IsLast属性告诉我此类别没有其他子类别。 IsLast设置为true的类别将为List<Recipe>

public class Category
{
    public int id { get; set; }
    public string categoryName { get; set; }
    public string categoryDesc { get; set; }
    public bool isLast { get; set; }
    public int parentId { get; set; }
    public int level { get; set; }
    public List<Category> Category { get; set; }
    public List<Recipe> Recipe { get; set; }
}


public class Recipe
{
    public int id { get; set; }
    public string RecipeName { get; set; }
    public string RecipeDesc { get; set; }

}

public class CategoryRecipe
{
    public int RecipeId { get; set; }
    public int CategoryId { get; set; }
}

我试过这样的事情,但下面的代码不起作用,请你提出一些方法。

public CategoryDto GetAllCategories(int parentId, int level)
{
    CategoryDto category = new CategoryDto();
    Category mainCategory = null;

    if (parentId == 0)
    {
        mainCategory = _categoryRepository.GetAll().Where(x => x.Level == 0).FirstOrDefault();
    }
    else
    {
        mainCategory = _categoryRepository.GetAll().Where(x => x.ParentId == parentId).FirstOrDefault();
    }

    if (mainCategory == null)
    {
        return null;
    }

    if (mainCategory.IsLast == true)
    {
        category.RecipeTemplate = ObjectMapper.Map<List<CategoryRecipe>>(_categoryRecipeTypesRepository.
            GetAll().Where(x => x.CategoryId == mainCategory.Id).ToList());
        return category;
    }

    var subcategories = _categoryRepository.GetAll().Where(x => x.ParentId == mainCategory.Id).ToList();


    var tempList = new List<Category>();
    foreach (Category cat in subcategories)
    {
        var subcategory = GetAllCategories(cat.Id, level + 1);

        if (subcategory != null)
        {
            tempList.Add(ObjectMapper.Map<Category>(subcategory)); //AutoMap
        }
    } 

    category.Category = tempList;

    return category;
}

0 个答案:

没有答案