Question

我正在努力构建一种可以打印急需模式的算法。代码如下：

public static void printPatternH(int size)
{
    for (int row = 1; row <= size; row++)
    {
        for (int col = 1; col <= 2*size; col++)
        {
            if (col > size + row - 1) {
                continue;
            }
            if (col <= size) {
                System.out.print((row + col >= size + 1 ? (row + col)%size : " ") + " ");
            }
            else {
                System.out.print((row + col >= size + 1 ? (row + size)%col : " ") + " ");
            }                
        }
        System.out.println();
    }
}

结果是：

我理解，如果size为9，则中间的最后一个数字将为0 (row + size)%col = 0，但是我无法找到修改它的方法，而不会更改其余部分值。

Answer 1

更改

(row + col)%size

到

(row + col - 1) % size + 1

Answer 2

你可以检查＆＃34; 0＆＃34;并在打印之前更换它。

                1 
              1 2 1 
            1 2 3 2 1 
          1 2 3 4 3 2 1 
        1 2 3 4 5 4 3 2 1 
      1 2 3 4 5 6 5 4 3 2 1 
    1 2 3 4 5 6 7 6 5 4 3 2 1 
  1 2 3 4 5 6 7 8 7 6 5 4 3 2 1 
1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1

它将提供此输出

{{1}}

Answer 3

尝试

public class Testb 
{
    int item = 9;
    int limit = 5;
    int half = item/2;
    public static void main(String[] args) 
    {
        //System.out.println("Hello World!");
        for(int i=0;i<limit;i++){

           for(int j=0;j<half;j++){

              if(j<(half-i)){

                 print(" ");

              }else{

                 print(j-(half-i))

              }          
           }

           print(i);

           for(int k=half;k<(half+i);k++){

               print((half+i)-(k+1));

           }

           println();
        }
    }
}

输出：

          0
        0 1 0
      0 1 2 1 0
    0 1 2 3 2 1 0
  0 1 2 3 4 3 2 1 0

希望对您有帮助

Answer 4

以下是您的问题的答案我希望这对你有所帮助

 int rowCount = 1;

    System.out.println("Here Is Your Pyramid");

    //Implementing the logic

    for (int i = noOfRows; i > 0; i--)
    {
        //Printing i*2 spaces at the beginning of each row

        for (int j = 1; j <= i*2; j++)
        {
            System.out.print(" ");
        }

        //Printing j value where j value will be from 1 to rowCount

        for (int j = 1; j <= rowCount; j++)             
        {
            System.out.print(j+" ");
        }

        //Printing j value where j value will be from rowCount-1 to 1

        for (int j = rowCount-1; j >= 1; j--)
        {                 
            System.out.print(j+" ");             
        }                          

        System.out.println();

        //Incrementing the rowCount

        rowCount++;
    }

Java使用嵌套for循环打印模式

4 个答案: