Question

Question is : I have to Create Function with below Details 
Function Name : Credit_Limit 
Input         : Entity_Id (Shipment_entity) 
Returns       : VARCHAR2 (Limit_Status)

设计规则：

如果给定实体ID的credit_limit大于50000，则将limit_status显示为＆＃39;信用额度大于50000＆＃39;
如果给定实体ID的credit_limit小于50000，则显示limit_status为＆＃39;信用额度小于50000＆＃39;

注意：请勿更改解决方案中的给定状态消息。

    CREATE OR REPLACE FUNCTION credit_limit (entity_id IN INTEGER)
         RETURN VARCHAR2
       IS
         c_credit_limit   NUMBER (5, 2);
         limit_status     VARCHAR (255);
        BEGIN
          SELECT credit_limit
             INTO c_credit_limit
           FROM shipment_entity
          WHERE id = entity_id;

    IF c_credit_limit > 50000
    THEN
        limit_status := 'Credit limit is greater than 50000';
    ELSE
        IF c_credit_limit < 50000
        THEN
            limit_status := 'Credit limit is less than 50000';
        END IF;
    END IF;

    RETURN (c_credit_limit);
    END;
    /

我执行上面提到的代码函数已创建，但在提交代码后显示错误的答案。帮助。

Answer 1

你想：

RETURN limit_status;

不

RETURN (c_credit_limit);

Answer 2

下面的功能正常

创建或替换功能credit_limit（entity_id IN INTEGER） RETURN VARCHAR2 IS c_credit_limit shipment_entity.credit_limit％TYPE; limit_status VARCHAR（255）; 开始选择credit_limit INTO c_credit_limit FROM shipment_entity WHERE id = entity_id;

IF c_credit_limit > 50000
THEN
    limit_status := 'Credit limit is greater than 50000';
ELSE
    IF c_credit_limit < 50000
    THEN
        limit_status := 'Credit limit is less than 50000';
    END IF;
END IF;

RETURN limit_status;
END;
/

Oracle数据库中的函数创建

2 个答案: