Question

我正在研究将JSON和/或XML中的一些数据解析成表。

我正在寻找帮助我解决这个问题的人。我需要将JSON或XML中的多个项解析到表中。下面我给出我的JSON示例：

{"appartments":[{"aptnum":"199","design":"open","sqft":"1200","extras":"covered parking","pool":"yes","moveinDate":"2019-01-01 13:12:01","link":"https:\/\/www.demoapts.com\/demo\/199"},{"aptnum":"223","design":"Built Already","sqft":"1800","extras":"covered parking","pool":"yes","moveinDate":"2018-05-09 00:12:01","link":"https:\/\/www.demoapts.com\/demo\/223"}]

我需要帮助的是将这些数据解析为html / Wordpress表。

我也使用了一种特殊类型的按钮，但我想如果我能学会如何正确解析数据，我就知道了。

我希望你们中的一些人可以帮助我并指出我正确的方向。我在谷歌搜索过，我只找到了从JSON中解析一个项目的例子。

Answer 1

以下是有关如何将此JSON结构解析为表

的示例

<?php
    $data = json_decode('{"appartments":[{"aptnum":"199","design":"open","sqft":"1200","extras":"covered parking","pool":"yes","moveinDate":"2019-01-01 13:12:01","link":"https:\/\/www.demoapts.com\/demo\/199"},{"aptnum":"223","design":"Built Already","sqft":"1800","extras":"covered parking","pool":"yes","moveinDate":"2018-05-09 00:12:01","link":"https:\/\/www.demoapts.com\/demo\/223"}]}');

    // Convert JSON string to PHP object.
    $appartments = $data->appartments;

    echo('<table>');
    if(!empty($appartments)){
        echo('<thead><tr>');
        // Using the first object to print column names.
        foreach($appartments[0] as $key => $value){
            echo('<th>' . $key . '</th>');   
        }
        echo('</tr></thead>');

        echo('<tbody>');
        // Iterate through all appartments and print them as table cells.
        foreach($appartments as $appartment){
            echo('<tr>');
            foreach($appartment as $key => $value){
                echo('<td>' . $value . '</td>');   
            }
            echo('</tr>');
        }

    echo('</tobdy></table>');
    }
?>

将JSON解析为表（Wordpress）

1 个答案: