Question

我有这个功能，但是zomato继续将其返回为403（无效的API）。我不确定是否还有其他功能/参数需要填充用户密钥

url='https://developers.zomato.com/api/v2.1/search?count=50&lat=111&lon=111&radius=1500&order=desc'
sendGetRequest() {
             const headers = new HttpHeaders()
                 .set('cache-control', 'no-cache')
                 .set('content-type', 'application/json')
                 .set('user-key', 'mykeygoeshere')

             return this.httpClient
                        .get(this.url, '', { headers: headers })
                        .subscribe(res => res.json);
    }

Answer 1

我已经通过生成API密钥尝试了搜索请求并获得了成功的响应。所以你需要有一个合适的API密钥。

请求：

curl -X GET --header "Accept: application/json" --header "user-key: a2716934XXXXXXXXXXXX21ced1a5a35" "https://developers.zomato.com/api/v2.1/search"

回复：

{ "results_found": 1272959, "results_start": 0, "results_shown": 20, "restaurants": [ { "restaurant": { "R": { "res_id": 17842104 }, "apikey": "a2716934XXXXXXXXXXXX21ced1a5a35", "id": "17842104", "name": "Mr.",

Angular 4 API HttpClient Post / Get in Zomato

1 个答案: