Question

我有下面的输入数组，

var temp = ['3_2', '3_2', '3_2', '4_2', '4_2', '5_2', '5_2' ]

那个，我需要拆分成下面的临时数组，

var temp1 = ['3_2', '3_2', '3_2']

var temp2 = ['4_2', '4_2']

var temp3 = ['5_2', '5_2']

Answer 1

您可以使用Object.values()和.reduce()：

var temp = ['3_2', '3_2', '3_2', '4_2', '4_2', '5_2', '5_2' ];

var result = Object.values(temp.reduce((a, c) => {
  let [v] = c.split('_');
  a[v] = a[v] || [];
  a[v].push(c);
  return a;
}, {}));

var [temp1, temp2, temp3] = result;

console.log(temp1);
console.log(temp2);
console.log(temp3);

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Answer 2

您可以使用带有变量引用的对象。

var temp = ['3_2', '3_2', '3_2', '4_2', '4_2', '5_2', '5_2'],
    temp1 = [],
    temp2 = [],
    temp3 = [],
    hash = { 3: temp1, 4: temp2, 5: temp3 };

temp.forEach(v => hash[v[0]].push(v));

console.log(temp1);
console.log(temp2);
console.log(temp3);

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Answer 3

这是一个解决方案

const base = ['3_2', '3_2', '3_2', '4_2', '4_2', '5_2', '5_2'];

const newArrays = base.reduce((tmp, x) => {
  const firstNumber = x.charAt(0);

  // Look if there is an array about the first number
  const index = tmp.findIndex(y => y[0].charAt(0) === firstNumber);

  // If there is no array yet, add one
  if (index === -1) {
    tmp.push([
      x,
    ]);

    return tmp;
  }

  // Push in existing array
  tmp[index].push(x);

  return tmp;
}, []);

console.log(newArrays);

Answer 4

使用Array.reduce()迭代数组。如果不存在子数组或者当前项不适合当前子数组，则添加子数组。始终将项目推送到最后一个子阵列。获得temp_1/2/3 destructuring的结果：reduce：

＆＃13;

const temp = ['3_2', '3_2', '3_2', '4_2', '4_2', '5_2', '5_2'];

const [temp_1, temp_2, temp_3] = temp.reduce((r, s) => {
  const key = s.split('_')[0];
  
  // if there isn't a sub array, or if the key doesn't fit the sub array, add a new sub array
  if(!r[r.length - 1] || !r[r.length - 1][0].startsWith(key)) {
    r.push([]);
  }
  
  // push to last subarry
  r[r.length - 1].push(s);
  
  return r;
}, []);

console.log('temp_1', temp_1);
console.log('temp_2', temp_2);
console.log('temp_3', temp_3);

＆＃13;

Answer 5

在提供的示例中，只有3个临时变量，但是，通常可以有许多变量，具体取决于测试用例。

您可以尝试以下

  var temp = ['3_2', '3_2', '3_2', '4_2', '4_2', '5_2', '5_2' ];


  var counter = 1;
  var map = {};

  temp.forEach(function(item){
    if(map[item]) {
      window["temp" + map[item]].push(item);
    } else {
      window["temp" + counter] = [item];
      map[item] = counter++;
    }
  });

  console.log(temp1);
  console.log(temp2);
  console.log(temp3);

此外，在上图中，我使用了window，您也可以存储在object中，然后将它们分配给变量

Answer 6

按照我创建的代码。

var temp = ['3_2', '3_2', '3_2', '4_2', '4_2', '5_2', '5_2' ];
var j = 0;
 this["temp"+j] = [];
for(var i=0; i<temp.length; i++)
{
   var name = temp[i];

   if($.inArray( name,  this["temp"+j]) > -1)
   {

     this["temp"+j].push(name);
   }
   else
   {
        j++;
      this["temp"+j] = [];
        this["temp"+j].push(name);
   }


}
console.log(temp1);
console.log(temp2);
console.log(temp3);

从单个数组中获取不同的数组

6 个答案: