给出完整的问题是,只是为了解决任何问题:
/**
* q1: Write a public class named ColonialFive with private instance variables named "fly" of
* type boolean, "blond" of type int, "tragic" of type boolean, and "top" of type String.
*
* Then write a public method inside the Problem Set class named "parseColonialFive" that
* takes a String as a parameter and returns an ArrayList of ColonialFive. This method will
* parse the input String as a properly formatted Json array of objects where each object
* represents the values for the instance of ColonialFive where the keys of each Json object
* are the instance variable names and the values are the values to which they should be set.
* Return an ArrayList of instances of ColonialFive with the instance variables matching the
* values from the Json objects. The order of instances in the ArrayList must match the order
* of objects in the Json array
*/
我的代码是:
public class ColonialFive {
private boolean fly;
private int blond;
private boolean tragic;
private String top;
public ColonialFive(boolean a, int b, boolean c, String d) {
this.fly = a;
this.blond = b;
this.tragic = c;
this.top = d;
}
public void setFly(boolean a) {
this.fly = a;
}
public void setBlond(int b) {
this.blond = b;
}
public void setTragic(boolean c) {
this.tragic = c;
}
public void setTop(String d) {
this.top = d;
}
}
public ArrayList<ColonialFive> parseColonialFive(String a1) {
ArrayList<ColonialFive> data = new ArrayList<ColonialFive>();
JsonValue jsonValue = Json.parse(a1);
JsonArray jsonArray = jsonValue.asArray();
for(int i =0;i<jsonArray.size();i++) {
JsonObject thisAble = jsonArray.get(0).asObject();
boolean a = thisAble.get("fly").asBoolean();
JsonObject jsonObject2 = jsonArray.get(1).asObject();
int b = jsonObject2.get("blond").asInt();
JsonObject civ = jsonArray.get(2).asObject();
boolean c = civ.get("tragic").asBoolean();
JsonObject pri = jsonArray.get(3).asObject();
String d =pri.get("top").asString();
ColonialFive h = new ColonialFive(a,b,c,d);
h.setFly(a);
h.setBlond(b);
h.setTragic(c);
h.setTop(d);
data.add(h);
}
return data;
}
当我运行代码时,我没有为每个即时变量获得正确的值。我不确定会出现什么问题,我也尝试过几种不同的方式来编写代码。
我不确定我是否应该使用JsonValue,它应该按原样工作,其他人甚至告诉我这样
答案 0 :(得分:1)
试试这个......
public ArrayList<ColonialFive> parseColonialFive(String a1) {
ArrayList<ColonialFive> data = new ArrayList<ColonialFive>();
JSONArray jArray = new JSONArray(a1);
if (jArray != null) {
for (int i=0;i<jArray.length();i++){
Gson gson = new Gson();
ColonialFive col= gson.fromJson(jArray.get(i).toString(), ColonialFive.class);
data.add(col);
}
}
return data;
}
public static void main(String[] args) {
String a1= "[{\"fly\": true, \"blond\": 42, \"tragic\": false, \"top\": \"Foo\"},{\"fly\": true, \"blond\": 42, \"tragic\": false, \"top\": \"Foo\"}]";
ArrayList<ColonialFive> data = new ColonialFive().parseColonialFive(a1);
System.out.println(data);
}
为此我使用两个jar文件 gson-2.2.2.jar 和 json.jar
答案 1 :(得分:1)
你可以试试这个:
public ArrayList<ColonialFive> parseColonialFive(String a1) {
ArrayList<ColonialFive> data = new ArrayList<ColonialFive>();
JSONArray jArray = new JSONArray(a1);
if (jArray != null) {
for (int i=0;i<jArray.length();i++){
Gson gson = new Gson();
ColonialFive col= gson.fromJson(jArray.get(i).toString(), ColonialFive.class);
data.add(col);
}
}
return data;
}
答案 2 :(得分:-1)
您每次都在检索第一个对象。
JsonObject thisAble = jsonArray.get(0).asObject();
将0
更改为i
。