HI〜大家好! 我已经获得了手机的registration_id和来自谷歌的身份验证令牌,用于执行推送的我的Gmail帐户。
但是当我将我的身份验证令牌和注册ID发送到Ubuntu并尝试通过php发布时,php的curl并且只卷曲请求C2DM获取消息。我总是得到401 Unauthorized。
这是我的PHP代码......
$post_params = array ( "Email" => $MY_GOOGLE_ACC, "Passwd" =>
$MY_GOOGLE_PWD, "accountType"=>"GOOGLE", "source=" . $MY_GOOGLE_SRC, "service=ac2dm" );
$first = true;
$data_msg = "";
foreach ($post_params as $key => $value) {
if ($first)
$first = false;
else
$data_msg .= "&";
$data_msg .= urlencode($key) ."=". urlencode($value);
}
$x = curl_init("https://www.google.com/accounts/ClientLogin");
curl_setopt($x, CURLOPT_HEADER, 1);
curl_setopt($x, CURLOPT_POST, 1);
curl_setopt($x, CURLOPT_POSTFIELDS, $data_msg);
curl_setopt($x, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($x);
curl_close($x);
$response = $data;
$authKey = trim(substr($response, 4+strpos($response, "SID=")));
echo $authKey; $collapse_key = 'something';
$post_params = array ( "registration_id" => $DEVICE_TOKEN, "collapse_key" =>
$collapse_key, "data.payload"=>"cakephp" );
$first = true;
$data_msg = "";
foreach ($post_params as $key => $value) {
if ($first)
$first = false;
else
$data_msg .= "&";
$data_msg .= urlencode($key) ."=". urlencode($value);
}
$size=strlen($data_msg);
$x = curl_init("https://android.apis.google.com/c2dm/send");
curl_setopt($x, CURLOPT_HTTPHEADER, array('Content-Type: application/x-www-form-urlencoded', 'Content-Length:'. $size, 'Authorization: GoogleLogin auth=' . $authKey));
curl_setopt($x, CURLOPT_HEADER, 1);
curl_setopt($x, CURLOPT_POST, 1);
curl_setopt($x, CURLOPT_POSTFIELDS, $data_msg);
curl_setopt($x, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($x);
curl_close($x);
$response = $data;
我是否想念某事或做错事?
任何帮助将不胜感激,谢谢!!
答案 0 :(得分:0)
您似乎从响应中提取SID,而不是Auth字段。
$authKey = trim(substr($response, 4+strpos($response, "SID=")));
应该是
$authKey = trim(substr($response, 5+strpos($response, "Auth=")));
尝试打印整个回复,您会看到类似的内容:
SID=DQAAAGgA...7Zg8CTN
LSID=DQAAAGsA...lk8BBbG
Auth=DQAAAGgA...dk3fA5N
这是你正在寻找的最后一个领域!