Question

是否可以＆＃34;规模＆＃34; pygame里面的一个矩形。有点像你在桌面上缩放窗口时，我想知道如何在pygame中这样做。您的光标将控制矩形的大小。

我使用了skrx方法，我尝试用2个矩形：

if evnt.type == MOUSEBUTTONDOWN:
        if winVirus.collidepoint(evnt.pos):
            rectVSelect = True
        elif winCrime.collidepoint(evnt.pos):
            rectCSelect = True
    elif evnt.type == MOUSEBUTTONUP:
        rectVSelect = False
        rectCSelect = False
    if evnt.type == MOUSEMOTION:
        if rectVSelect:
            winVirus.w += evnt.rel[0]
            winVirus.h += evnt.rel[1]
            winVirus.w = max(winVirus.w, 50)
            winVirus.h = max(winVirus.h, 50)  
        elif rectCSelect:
            winCrime.w += evnt.rel[0]
            winCrime.h += evnt.rel[1]
            winCrime.w = max(winVirus.w, 50)
            winCrime.h = max(winVirus.h, 50)

但对于第二个矩形，它会正常移动，似乎是＆＃34; winCrime＆＃34;的问题。 winVirus＆＃34;工作得非常好。

Answer 1

您只需更改rect的宽度和高度（w和h属性）。当鼠标移动时（MOUSEMOTION事件被添加到队列中）并且如果选择了矩形，则将相对移动event.rel添加到宽度和高度。

import pygame as pg


pg.init()
screen = pg.display.set_mode((640, 480))
clock = pg.time.Clock()
rect = pg.Rect(100, 100, 161, 100)
rect_selected = False

done = False
while not done:
    for event in pg.event.get():
        if event.type == pg.QUIT:
            done = True
        elif event.type == pg.MOUSEBUTTONDOWN:
            # Set rect_selected to True when the user clicks on the rect.
            if rect.collidepoint(event.pos):
                rect_selected = True
        elif event.type == pg.MOUSEBUTTONUP:
            rect_selected = False
        elif event.type == pg.MOUSEMOTION:
            if rect_selected:
                # Simply adjust the width and the height of the screen
                # by subtracting the relative mouse movement.
                rect.w += event.rel[0]
                rect.h += event.rel[1]
                # 10*10 px is the minimal size, so that the rect can
                # still be clicked.
                rect.w = max(rect.w, 10)
                rect.h = max(rect.h, 10)

    screen.fill((30, 30, 30))
    pg.draw.rect(screen, (0, 100, 250), rect)
    pg.display.flip()
    clock.tick(30)

如果你想用几个rects做这个，你可以将点击的rect分配给变量（在这种情况下为selected_rect），然后缩放它。

import pygame as pg


pg.init()
screen = pg.display.set_mode((640, 480))
clock = pg.time.Clock()
rect1 = pg.Rect(100, 100, 161, 100)
rect2 = pg.Rect(300, 200, 161, 100)
selected_rect = None

done = False
while not done:
    for event in pg.event.get():
        if event.type == pg.QUIT:
            done = True
        elif event.type == pg.MOUSEBUTTONDOWN:
            # Set selected_rect to the colliding rect.
            for rect in (rect1, rect2):
                if rect.collidepoint(event.pos):
                    selected_rect = rect
        elif event.type == pg.MOUSEBUTTONUP:
            selected_rect = None  # De-select.
        elif event.type == pg.MOUSEMOTION:
            if selected_rect is not None:  # Scale if a rect is selected.
                selected_rect.w += event.rel[0]
                selected_rect.h += event.rel[1]
                selected_rect.w = max(selected_rect.w, 10)
                selected_rect.h = max(selected_rect.h, 10)

    screen.fill((30, 30, 30))
    pg.draw.rect(screen, (0, 100, 250), rect1)
    pg.draw.rect(screen, (0, 200, 120), rect2)
    pg.display.flip()
    clock.tick(30)

Answer 2

这是一个有效的例子。你将不得不适应你的情况。

import pygame

rect = pygame.Rect(50, 50, 100, 100)
screen = pygame.display.set_mode((200, 200))

running = True
while running:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False
        elif event.type == pygame.MOUSEMOTION and event.buttons[0]:
            p = event.pos[0] - event.rel[0], event.pos[1] - event.rel[1]
            if pygame.Rect(rect.left, rect.top - 2, rect.width, 4).collidepoint(*p): # top
                rect = pygame.Rect(rect.left, rect.top + event.rel[1], rect.width, rect.height - event.rel[1])
            elif pygame.Rect(rect.left, rect.bottom - 2, rect.width, 4).collidepoint(*p): # bottom
                rect = pygame.Rect(rect.left, rect.top, rect.width, rect.height + event.rel[1])
            if pygame.Rect(rect.left - 2, rect.top, 4, rect.height).collidepoint(*p): # left
                rect = pygame.Rect(rect.left + event.rel[0], rect.top, rect.width - event.rel[0], rect.height)
            elif pygame.Rect(rect.right - 2, rect.top, 4, rect.height).collidepoint(*p): # right
                rect = pygame.Rect(rect.left, rect.top, rect.width + event.rel[0], rect.height)

    screen.fill((0, 0, 0))
    pygame.draw.rect(screen, (255, 255, 255), rect)
    pygame.display.update()

在Pygame中缩放图像/矩形

2 个答案: